Answer:
588 N
Explanation:
Since the 60 kg is moving at a constant velocity there is no acceleration. In order for the system to be balanced, both the normal force and the force of gravity must be equal. In this case the man has a mass of 60 kg. So to find the force you multiply mass by gravitys constant (9.81). And you end up with an answer of 588.6 but I rounded to 588.
Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
Answer:
<em>The velocity of the two cars is 10 m/s after the collision.</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=m.v
If we have a system of bodies, then the total momentum is the sum of them all
If some collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, the law of conservation of linear momentum takes the form:
If both masses stick together after the collision at a common speed v', then:
The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).
Knowing both cars stick and move together after the collision, their velocity is found solving for v':
v' = 10 m/s
The velocity of the two cars is 10 m/s after the collision.
E = 300km * 2000J/km = 600000J
The rotational energy is given by:
E = 0.5 * I * ω²
I for a uniform cylinder is given by:
I = 0.5 * m * r²
Resulting equation:
E = 0.25 * m * r² * ω²
Given values:
ω = 430 rev/s = 430 * 2π / s
E = 600000
Solve for r.