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Alecsey [184]
3 years ago
13

a mass of 10kg is placed on a horizontal table with coefficient of friction is 0.5. if the mass is static, determine weight of t

he object against the horizontal table and the limiting frictional force.​
Physics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

10

Explanation:

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A mixture of nitrogen and xenon gases, at a total pressure of 836 mm Hg, contains 2.80 grams of nitrogen and 24.9 grams of xenon
larisa86 [58]

Answer: Partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

Explanation:

The partial pressure of a gas is given by Raoult's law, which is:

p_A=p_T\times \chi_A

where,

p_A = partial pressure of substance A

p_T = total pressure

\chi_A = mole fraction of substance A

We are given:

m_{N_2}=2.80g

m_{Xe}=24.9g

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

And,

n_A=\frac{m_A}{M_A}

Mole fraction of nitrogen is given as:

\chi_{N_2}=\frac{\frac{m_{N_2}}{M_{N_2}}}{(\frac{m_{N_2}}{M_{N_2}}+\frac{m_{Xe}}{M_{Xe}})}

Molar mass of N_2 = 28 g/mol

Molar mass of Xe =  g/mol

Putting values in above equation, we get:

\chi_{N_2}=\frac{\frac{2.80}{28}}{\frac{2.80}{28}+\frac{24.9}{131}}

\chi_{N_2}=\frac{0.100}{0.100+0.190}=0.345

To calculate the mole fraction of xenon, we use the equation:

\chi_{Xe}+\chi_{N_2}=1\\\\\chi_{Xe}=1-0.345=0.655

p_{N_2}=836mmHg\times 0.345=288mmHg

p_{Xe}=836mmHg\times 0.655=548mmHg

Thus partial pressure of nitrogen and xenon are 288mmHg and 548 mmHg respectively.

6 0
3 years ago
You are working in the finance department of Innotech Ltd (INT). The Company has spent $5 million
lozanna [386]

Answer: The Company has spent $5 million in research and development over the past 12 months developing cutting-edge battery technology which will be incorporated ...

Explanation: uhmmmmmm i dont know this one but it is pretty ez

5 0
3 years ago
Which of the following can be computed?
Musya8 [376]
Answer: only the third option. [Vector A] dot [vector B + vector C]

The dot between the vectors mean that the operation to perform is the "scalar product", alson known as "dot product".

This operation is only defined between two vectors, not one scalar and one vector.

When you perform, in the first option, the dot product of any ot the first and the second vectors you get a scalar, then you cannot make the dot product of this result with the third vector.

For the second option, when you perform the dot product of vectar B with vector C you get a scalar, then you cannot make the dot product ot this result with the vector A.

The third option indicates that you sum the vectors B and C, whose result is a vector and later you make the dot product of this resulting vector with the vector A. Operation valid.

The fourth option indicates the dot product of a scalar with the vector A, which we already explained that is not defined.
5 0
3 years ago
Radioactive isotopes of an atom are:
Len [333]

Radioactive isotopes of an atom aren't as stable as you would think, so the correct answer is: C. Less Stable

(I can verify this because I took the test.)

Hope this helps! Have a wonderfully wonderful day!

Cheers mate!

8 0
3 years ago
Read 2 more answers
A jet travels at 489 meters per second how long does it take to travel 235 m? answer in seconds
Sladkaya [172]

if in 1 second the jet goes 428 meters and you want to know how long it takes to go 237 meters you just divide 237/428  

it can be written like this  

_1_ = __x__  

428 237  

cross multiply  

428 times x = 1 times 237  

428x=237  

divide by 428 on both sides  

x= 237/428  

x=0.5537 seconds

7 0
3 years ago
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