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2 years ago

A lightbulb has a resistance of 195 Ω and carries a current of 0.62 A.

Physics

1 answer:

ki77a [65]2 years ago

8 0

Answer:

Explanation:

Power is current times voltage:

P = IV

Voltage is current times resistance:

V = IR

Therefore:

P = I²R

Given I = 0.62 A and R = 195 Ω:

P = (0.62 A)² (195 Ω)

P ≈ 75 W

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Explanation:

Let's start by reviewing some definitions about waves:

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Learn more about waves, frequency and period:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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