Answer:
V₂ = 27 L
Explanation:
Given data:
Initial volume = 15 L
Initial temperature = 125 K
Final temperature = 225 K
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 15 L × 225K / 125 k
V₂ = 3375 L.K / 125 K
V₂ = 27 L
The answer is 59.01 g
If a 100-gram sample of NaCl consists of 39.34 g of sodium, a 150-gram sample of NaCl will consist x g of sodium:
100 g : 39.34 g = 150 g : x
x = 39.34 g * 150 g : 100 g
x = 59.01 g
Complete Question
Question 096 Propose a three-step synthetic sequence to accomplish the transformation below.
Option 1 => 1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2CCNa
Option 2 => 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa
Option 3 => 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa
Option 4 => 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR
Option 5 => 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa
Option 6 => 1) NaOEt; 2) NBS, hν; 3) NaSBu
Answer:
The correct option is option 5
Explanation:
The mechanism of the reaction is shown on the first uploaded image
The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.
Evidently, the shell with energy level one has no p orbital.
- Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.
- However, we must know that the p-orbital comprises of 3 sub-orbitals namely;
p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.
- Therefore, the total number of electrons in the p orbital is 6 electrons.
In essence, the element in question should have electron configuration;
- 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
The electron configuration above contains 54 electrons and has atomic number, 54.
In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.
Read more:
brainly.com/question/2183111
Answer:
Balanced chemical equation:
C₃H₈ + 5O₂ → 4H₂O + 3CO₂
Explanation:
Chemical equation:
C₃H₈ + O₂ → H₂O + CO₂
Balanced chemical equation:
C₃H₈ + 5O₂ → 4H₂O + 3CO₂
1st step:
Left side Right side
C = 3 C = 1
H = 8 H = 2
O = 2 O = 3
2nd step:
C₃H₈ + O₂ → H₂O + 3CO₂
Left side Right side
C = 3 C = 1×3 = 3
H = 8 H = 2
O = 2 O = 6+1 = 7
3rd step:
C₃H₈ + O₂ → 4H₂O + 3CO₂
Left side Right side
C = 3 C = 1×3 = 3
H = 8 H = 2×4 = 8
O = 2 O = 6+4 = 10
4th step:
C₃H₈ + 5O₂ → 4H₂O + 3CO₂
Left side Right side
C = 3 C = 1×3 = 3
H = 8 H = 2×4 = 8
O = 2×5= 10 O = 6+4 = 10
