It’s the first 1 M yea it’s the first one
The combined gas law equation has been 
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The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.
In an ideal gas the equation has been given as:
Where, <em>P </em>has been the pressure of the gas
<em>V </em>has been the volume of the gas
<em>n </em>has been the moles of the gas
<em>R </em>has been a constant
<em>T </em>has been the temperature of the gas
The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:
For more information about combined gas law, refer to the link:
brainly.com/question/13154969
I'd say that the answer is erosion
Answer:
symbol= F
proton= 9
neutron= 19 I understand this is it ok for you
Iridium-192 is used in cancer treatment, a small cylindrical piece of 192 Ir, 0.6 mm in diameter (0.3mm radius) and 3.5 mm long, is surgically inserted into the tumor. if the density of iridium is 22.42 g/cm3, how many iridium atoms are present in the sample?
Let us start by computing for the volume of the cylinder. V = π(r^2)*h where r and h are the radius and height of the cylinder, respectively. Let's convert all given dimensions to cm first. Radius = 0.03 cm, height is 0.35cm long.
V = π * (0.03cm)^2 * 0.35 cm = 9.896*10^-4 cm^3
Now we have the volume of 192-Ir, let's use the density provided to get it's mass, and once we have the mass let's use the molar mass to get the amount of moles. After getting the amount of moles, we use Avogadro's number to convert moles into number of atoms. See the calculation below and see if all units "cancel":
9.896*10^-4 cm^3 * (22.42 g/cm3) * (1 mole / 191.963 g) * (6.022x10^23 atoms /mole)
= 6.96 x 10^19 atoms of Ir-122 are present.
