Answer: The value of
for the given reaction is
.
Explanation:
The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.
It is denoted by the symbol
.
For example, ![H_{2} + I_{2} \rightarrow 2HI](https://tex.z-dn.net/?f=H_%7B2%7D%20%2B%20I_%7B2%7D%20%5Crightarrow%202HI)
The expression for
of this reaction is as follows.
So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of
for the given reaction.
Thus, we can conclude that the value of
for the given reaction is
.
mass = Density x Volume
2.00 x 0.160 = 0.32 grams
The mass of Au is 19.7 g
The chemical reaction may be
Au₂S₃ + 3H₂ → 2Au + 3H₂S
1 mole of Au₂S₃ gives 2 mole of Au
Then 0.0500 mol of Au₂S₃ gives
0.0500 × 2 / 1
= 0.10 moles.
To find mass
Mass = moles × molar mass
Moles = 0.10.
Molar mass = 197 g
Mass = 0.10 × 197
= 19.7 g
Hence the mass of Au produces is 19.7 g
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Answer:
When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt.
Explanation:
Answer:
The answer to your question is: 14 g of N₂
Explanation:
Data
MW N2 = 14
MW H2 = 1
MW NH3 = 17
N₂(g) + 3H₂(g) ---> 2NH₃(g).
28g 6g 34g
28 g of N₂ -------------------- 6 g of H₂
x -------------------- 3 g of H₂
x = (3 x 28) / 6
x = 14 g of N₂