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astraxan [27]
3 years ago
8

A 4.00 gram sample of a solution of sodium chloride in water was heated until all the water had evaporated. The sodium chloride

that remained weighed 1.22 grams. Calculate the percentage of water in the original 4.00 grams of solution.
Chemistry
1 answer:
eimsori [14]3 years ago
7 0

<u>Answer:</u> The mass percent of water in the original sample is 69.5 %

<u>Explanation:</u>

We are given:

Mass of NaCl remained after heating = 1.22 grams

Mass of the sample = 4.00 grams

Mass of water evaporated = Mass of sample - Mass of NaCl remained

Mass of water evaporated = (4.00 - 1.22) g = 2.78 grams

To calculate the mass percentage of water in the sample, we use the equation:

\text{Mass percent of water}=\frac{\text{Mass of water}}{\text{Mass of sample}}\times 100

Mass of water = 2.78 g

Mass of sample = 4.00 g

Putting values in above equation, we get:

\text{Mass percent of water}=\frac{2.78g}{4.00g}\times 100=69.5\%

Hence, the mass percent of water in the original sample is 69.5 %

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If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra
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(b) The number of oxygen atoms are, 27.099\times 10^{23}

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Explanation : Given,

Mass of CrO_3 = 150 g

Molar mass of CrO_3 = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of CrO_3.

\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles

The moles of CrO_3 is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

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According to the mole concept,

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The number of oxygen atoms are, 27.099\times 10^{23}

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of CrO_3 contains 3 moles of oxygen

So, 1.5 mole of CrO_3 contains 1.5\times 3=4.5 moles of oxygen

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\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g

The mass of oxygen is, 72 grams.

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