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astraxan [27]
3 years ago
8

A 4.00 gram sample of a solution of sodium chloride in water was heated until all the water had evaporated. The sodium chloride

that remained weighed 1.22 grams. Calculate the percentage of water in the original 4.00 grams of solution.
Chemistry
1 answer:
eimsori [14]3 years ago
7 0

<u>Answer:</u> The mass percent of water in the original sample is 69.5 %

<u>Explanation:</u>

We are given:

Mass of NaCl remained after heating = 1.22 grams

Mass of the sample = 4.00 grams

Mass of water evaporated = Mass of sample - Mass of NaCl remained

Mass of water evaporated = (4.00 - 1.22) g = 2.78 grams

To calculate the mass percentage of water in the sample, we use the equation:

\text{Mass percent of water}=\frac{\text{Mass of water}}{\text{Mass of sample}}\times 100

Mass of water = 2.78 g

Mass of sample = 4.00 g

Putting values in above equation, we get:

\text{Mass percent of water}=\frac{2.78g}{4.00g}\times 100=69.5\%

Hence, the mass percent of water in the original sample is 69.5 %

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As, 2 mole of  react to give 5 moles of carbon

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3 years ago
Why do we balance chemical reaction
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Hey there!

We balance chemical equations because of the law of conservation of mass.

The law of conservation of mass states that matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.

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3 0
3 years ago
How many grams of Fe2O3 are formed when 16.7 moles of Fe reacts completely with
lesantik [10]

Answer:

The answer to your question is 1) 1336 g of Fe₂O₃  2) 1 mol of H₃PO₄

Explanation:

1)

Data

mass of Fe₂O₃ = ?

moles of Fe = 16.7

Balanced chemical reaction

                 4Fe  +  3O₂  ⇒   2Fe₂O₃

a.- Calculate the moles of Fe₂O₃

                 4 moles of Fe ----------------- 2 moles of Fe₂O₃

                16.7 moles of Fe --------------  x

                                    x = (16.7 x 2)/4

                                    x = 33.4/4

                                    x = 8.35 moles of Fe₂O₃

b.- Calculate the molar mass of Fe₂O₃

Fe₂O₃ = (2 x 56)+ (3 x 16) = 112 + 48 = 160 g

c.- Convert moles to mass

                       160 g of Fe₂O₃ ------------ 1 mol

                          x                     ------------ 8.35 moles of Fe₂O₃

                          x = (8.35 x 160)/1

                          x = 1336 g of Fe₂O₃

2)

moles of H₃PO₄ = ?

mass of P₄O₁₀ = 71 g

Balanced chemical reaction

         P₄O₁₀ + 6H₂O ⇒ 4H₃PO₄

a.- Calculate the molar mass of P₄O₁₀

P₄O₁₀ = (31 x 4) + (16 x 10) = 124 + 160 = 284 g

b.- Convert the mass of P₄O₁₀ to moles

                   284 g ------------------- 1 mol

                     71 g -------------------- x

                       x = (71 x 1)/284

                       x = 0.25 moles of P₄O₁₀

c.- Calculate the moles of H₃PO₄

                   1 mol of P₄O₁₀ ---------------- 4 moles of H₃PO₄

                  0.25 moles     -----------------  x

                      x = (0.25 x 4) / 1

                     x = 1 mol of H₃PO₄

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Answer:

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Explanation:

halogen, any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and tennessine (Ts).

Due to their high effective nuclear charge, halogens are highly electronegative. Therefore, they are highly reactive and can gain an electron through reaction with other elements.

Halogens are very reactive because they have seven valence electrons and need one more to have eight valence electrons (an octet). They react with metals and other halogens to get an octet. When this happens, the atoms become stable and have noble gas configurations.

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