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Nady [450]
3 years ago
6

If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution, what is the concentration of sodium chloride in the dilute

d solution? A) 0.250 MM B) 1.13 M C) 0.500 M D) 0.450 M E) none of the above
Chemistry
1 answer:
Naddik [55]3 years ago
7 0

Answer:

D) 0.450 M

Explanation:

Given data

  • Initial volume (V₁): 6.00 mL
  • Initial concentration (C₁): 0.750 M
  • Volume of water (VH₂O): 4.00 mL
  • Final volume (V₂): V₁ + VH₂O = 6.00 mL + 4.00 mL = 10.0 mL
  • Final concentration (C₂): ?

We can determine the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.750 M × 6.00 mL/10.0 mL

C₂ = 0.450 M

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3 years ago
Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and
Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

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This means,

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Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%

Then,

Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%

Percent\ yield\ of\ copper\ hydroxide= 84\%

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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3 years ago
__ bonds are characterized by the sharing of electrons between the participating atoms.
FrozenT [24]
I think the answer is B
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4 years ago
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What quantity in moles of HCl are there in 35.0 mL of 0.350 M HCl?
marta [7]

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter)  x  volume of solution (liter)

First convert your volume to L instead of mL.  35mL = 0.035L

moles  =  0.350 moles/liter   x    0.035 liter  (liters cancel out)

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3 years ago
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