All categories

3 years ago

What quantity in moles of HCl are there in 35.0 mL of 0.350 M HCl?

Chemistry

1 answer:

marta [7]3 years ago

5 0

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter) x volume of solution (liter)

First convert your volume to L instead of mL. 35mL = 0.035L

moles = 0.350 moles/liter x 0.035 liter (liters cancel out)

moles = 0.0123

You might be interested in

How many grams of NaNO3 can be dissolved in 200mL of water at 40 degrees Celsius?

Tju [1.3M]

Answer:

I think the answer is, 100.

Explanation:

but i dont know try

6 0

3 years ago

Which type of substance can separated using a centrifuge?<br>

Natasha2012 [34]

Answer:

Its separates the components of heterogeneous mixtures.

like examples :-

liquids in liquids,
solids in liquids,
solids and liquids in gases.

4 0

3 years ago

The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t

const2013 [10]

Answer:

$\boxed{\text{47.4 g}}$

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 17.03 32.00 18.02

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g: 70.1 70.1

Step 1. Calculate the moles of each reactant

$\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}$

Step 2. Identify the limiting reactant

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

$\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}$

From O₂:

The molar ratio of H₂O:O₂ is 6:5.

$\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}$

O₂ is the limiting reactant because it gives the smaller amount of H₂O.

Step 3. Calculate the theoretical yield.

$\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}$

6 0

3 years ago

Which statement best describes John Dalton’s use of creativity in his work?

asambeis [7]

<span>The scientist thought that the atom was the smallest particle in the universe is John Dalton. He established the atomic theory which consists of five; elements are made of extremely small particles called atoms, atoms of different element have different sizes, mass and physic – chemical properties, atoms cannot be divided further, destroyed or created, atoms can combine to form compounds and in chemical reaction, atoms can be combined, separated or rearranged</span>

6 0

3 years ago

Number of moles of sodium azide<br>

Basile [38]

Answer:

0.015382279644614 mole.

3 0

3 years ago

Read 2 more answers