All categories

2 years ago

What quantity in moles of HCl are there in 35.0 mL of 0.350 M HCl?

Chemistry

1 answer:

marta [7]2 years ago

5 0

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter) x volume of solution (liter)

First convert your volume to L instead of mL. 35mL = 0.035L

moles = 0.350 moles/liter x 0.035 liter (liters cancel out)

moles = 0.0123

You might be interested in

Give the number of atoms of each type of sodium carbonate

Bad White [126]

Answer:What is the question

Explanation:

6 0

2 years ago

What is the Equation of Reduction in Mg+F2 gives MgF2, I WILL MARK YOU AS BRAINLIST

skad [1K]

Answer:

Mg+F2= Mgf2

Explanation:

F 2 is an oxidizing agent, Mg is a reducing agent. ; Pale-yellow to greenish gas with a pungent, irritating odor.

5 0

2 years ago

In order for a cell to continue being efficient at exchanging materials, what must it do to maintain its surface-to-volume ratio

aksik [14]

Explanation:

It will have to change its form in order for the cell to focus on developing and retaining a viable, in order to be large and narrow as in the situation of the nerve cells or to build a more 'contoured' surface, that is, to establish microvillus.

4 0

2 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

We have:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

Where M is the molar mass of NaOH = 39.9 g/mol

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

3 0

3 years ago

The mass and volume of each sample differ from the mass and volume of the other samples. Is it possible for each sample to conta

andrew11 [14]

The mass and volume of each sample differ from the mass and volume of the other samples. Is it possible for each sample to contain 1 mol of each substance?

C) Yes, because the number of moles is not dependent on the mass or the volume.

5 0

3 years ago

Read 2 more answers