Answer:
Explanation:
We shall apply law of conservation of momentum to solve the problem .
Helium-3 collides with nitrogen-14 at rest . After the collision the newly formed deuterium atom and oxygen-15 atom moves .
momentum before the collision
= 3.016 x 6.346 x 10⁶ + 14.003 x 0 = 19.14 x 10⁶ unit
momentum after collision
2.014 x 1.531 x 10⁷ + 15.003 V
3.083 x 10⁷ + 15.003 V units
Applying the law of conservation of momentum ,
19.14 x 10⁶ = 3.083 x 10⁷ + 15.003 V
1.914 x 10⁷ = 3.083 x 10⁷ + 15.003 V
15.003 V = - 1.169 x 10⁷
V = .077917 x 10⁷
= 7.79 x 10⁵ m /s
= .0779 x 10⁷ m /s
mass of helium atom = 3.016 u = 3.016 x 1.67 x 10⁻²⁷ kg
velocity = 6.346 x 10⁶ m /s
kinetic energy = 1 /2 x 3.016 x 1.67 x 10⁻²⁷ x (6.346 x 10⁶ )²
= 101.42 x 10⁻¹⁵ J
kinetic energy of nitrogen atoms = 0
Total energy before collision = 101.42 x 10⁻¹⁵ J
Similarly kinetic energy after collision
= 1 /2 x [ 2.014 x 1.531² + 15.003 x .0779² ] x 1.67 x 10⁻²⁷ x 10¹⁴
= .835 x [ 4.72 + .09 ] x 10⁻¹³ J
= 4.016 x 10⁻¹³ J
= 401.6 x 10⁻¹⁵ J
value of kinetic energy is increased .
