What the unit of work?

A student has been assigned to measure the density of an irregularly shaped piece of metal.which apparatus would be more appropr

SOVA2 [1]

Complete Question:

A student has been assigned to measure the density of an irregularly shaped piece of metal.

Which apparatus would be most appropriate to carry out this task?

Group of answer choices

A. ruler, balance

B. beaker, crucible

C. flask, Bunsen burner

D. graduated cylinder, balance

Answer:

D. graduated cylinder, balance

Explanation:

In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.

The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.

A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.

3 0

2 years ago

Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a

jolli1 [7]

Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

v = vy₀/sinθ

v = 4.9/sin32

v = 9.2466...

v = 9.2 m/s

8 0

2 years ago

For a short time the missile moves along the parabolic path y=(18−2x2) km. If motion along the ground is measured as x=(4t−3) km

muminat

Answer with Explanation:

We are given that

$y=(18-2x^2) km$

$x=(4t-3)km$

Differentiate x and y w.r.t t

$\frac{dx}{dt}=4$

$\frac{dy}{dt}=-4x\frac{dx}{dt}$

$\frac{dy}{dt}=-4x\times 4=-16x=-16(4t-3)$

$v_x=\frac{dx}{dt}=4$

$v_y=\frac{dy}{dt}=-16(4t-3)$

Substitute t=1

$v_x=4$

$v_y=-16(4-3)=-16$

Magnitude of velocity= $\mid v\mid=\sqrt{v^2_x+v^2_y}$

$\mid v\mid=\sqrt{4^2+(-16)^2}=16.49 m/s$

Hence, the magnitude of the missile's velocity=16.49 m/s

$a_x=\frac{d(\frac{dx}{dt})}{dt}=\frac{d(4)}{dt}=0$

$a_y=\frac{d(\frac{dy}{dt})}{dt}=\frac{d(-16(4t-3))}{dt}=-64$

Substitute t=1

$a_x=0,a_y=-64$

$\mid a\mid=\sqrt{a^2_x+a^2_y}$

$\mid a\mid=\sqrt{0+(-64)^2}=64m/s^2$

Hence, the magnitude of acceleration when t=1 s= $64m/s^2$

3 0

2 years ago

Match the choices to the appropriate blank . Use each choice only once.

pav-90 [236]

Answer:

1. about 1.5 AU

2. about 5 AU

3. about 8 light-years

4. about 100,000 light-years

5. less than 0.01 AU

Explanation:

a. Mars is about 1.5 AU from the Sun.

b. Jupiter is about 5 AU from the Sun.

c. The star Sirius is about 8 light-years from the Sun.

d. The diameter of the Milky Way Galaxy is about 100,000 light-years.

e. The distance from Earth to the Moon is less than 0.01 AU.

Note: AU is an acronym for Astronomical Unit and it is a standard unit by astronomers to illustrate the distance between the planetary bodies found in the solar system.

5 0

2 years ago

A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe

KIM [24]

Answer: V = 15 m/s

Explanation:

As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately.

8 0

2 years ago

What the unit of work?​

What the unit of work?