Explanation:
The runner runs for a total time of
\Delta t=10.0 min= 600 sΔt=10.0min=600s
The energy converted by the runner during this time is equal to the power of the runner times the total time:
E=P \Delta t=400 W \cdot 600 s =2.4 \cdot 10^5 JE=PΔt=400W⋅600s=2.4⋅10
5
J
Answer:
The upward buoyancy force on an object acts through the overall center of buoyancy, being the centroid of the displaced volume of fluid. The weight force on the object acts through its center of gravity.
108 681(nearest whole day)
Answer:
It would take
time for the capacitor to discharge from
to
.
It would take
time for the capacitor to discharge from
to
.
Note that
, and that
.
Explanation:
In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is
, and the initial charge of the capacitor be
. Then at time
, the charge stored in the capacitor would be:
.
<h3>a)</h3>
.
Apply the equation
:
.
The goal is to solve for
in terms of
. Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
<h3>b)</h3>
.
Apply the equation
:
.
The goal is to solve for
in terms of
. Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the average velocity at which the supplies are travelling in air. The formula to be used here if the completed question is obtained is
Average velocity (in m/s) = distance (m) ÷ time (s)
Since we are looking for the time, then time should be made the subject of the formula
time (in secs) = distance ÷ average velocity