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Ludmilka [50]
3 years ago
11

A sample was recorded to have 15.0 grams of hydrogen gas, how many liters would this be?

Chemistry
1 answer:
laiz [17]3 years ago
6 0

Answer:

168 L

Explanation:

Given data:

Mass of hydrogen gas = 15 g

Volume occupied = ?

Solution:

First of all we will calculate the number of moles of hydrogen gas.

Number of moles = mass/ molar mass

Number of moles = 15 g/ 2 g/mol

Number of moles = 7.5 mol

One mole of any gas at STP occupy 22.4 L volume.

The standard temperature and pressure is 0°C and 1 atm.

Thus the volume occupy by the 7.5 moles hydrogen gas is,

7.5 mol × 22.4 L/1 mol = 168 L

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A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c
andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=31.8 +273= 304.8 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}

Moles = 1.905 moles

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0
2 years ago
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