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stellarik [79]
3 years ago
14

Which is a reason that a chemical engineer would use a rate law for a reaction in a chemical plant?

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0

actually the answer is C for anyone that still needs it.

White raven [17]3 years ago
5 0
So that maybe it would be stable?
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Match the statements with the atmospheric layer they describe.
vekshin1

The correct matches are:

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This is the top layer of the atmosphere. The atoms are so dispersed that despite it having very high temperature it doesn't feel like it at all.

2. Thermosphere - Particles that have enough energy can escape into space

The thermosphere is the fourth highest layer of the atmosphere. The atoms in this layer are relatively distant from one another, so the particles that have enough energy manage to escape easily into the exosphere and then the space.

3. Mesosphere - It is the coldest region of the atmosphere

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6 0
4 years ago
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How many litres of fluorine gas at stp can be collected from the decomposition of 90.7 g of AuF3
7nadin3 [17]

Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

Explanation:

The balanced decomposition reaction is shown as

2AuF_3\rightarrow 2Au+3F_2

moles of AuF_3=\frac{\text {given mass}}{\text {Molar mass}}=\frac{90.7g}{254g/mol}=0.36moles

According to stoichiometry:

2 moles of AuF_3 gives = 3 moles of flourine gas

Thus 0.36 moles of AuF_3 gives = \frac{3}{2}\times 0.36=0.54moles of flourine gas

Using ideal gas equation :

PV=nRT

P = pressure of gas = 1 atm ( at STP)

V = Volume of gas = ?

n = moles of gas = 0.54

R = gas constant = 0.0821 L atm/Kmol

T = temperature = 273 K ( at STP)

Putting the values we get :

1atm\times V=0.54mol\times 0.0821Latm/Kmol\times 273K

V=12L

Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

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