Electronic Configuration of Cu⁴⁺ is written using these two steps;
Step I:
Write the Electronic Configuration of Copper (Cu).
As Atomic Number of Cu = 29
So,
1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹
Rearranging it in order of increasing orbital energy,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
Cu = [Ar] 4s¹, 3d¹⁰
Step II:
Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
Cu⁴⁺ = [Ar] 3d⁷
this is what I got 6NPbO+KI
Hope this helped
No idea , sorry. maybe it is.....actually i dont know, sooo sorry
C. Electrons fill orbitals in order of increasing orbital energy.
