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Damm [24]
3 years ago
10

Write two decimals greater than luke's decimal and less than bekka's decimal

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0
.23 and .24 is your answer.
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An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
50+25 POINTS!!! PLZ HELP WILL GIVE BRAINLIEST!!!
frosja888 [35]

3x-2 if x is less an or greater than 1,  will be a negative y value.

-2x+3 when x is greater than 1 will also be a negative y value.


The graph would be the first one ( an upside down V)

5 0
3 years ago
Read 2 more answers
Help me please
kari74 [83]

Answer:

\frac{ \cos(80) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(70) }  = 2 \\  \frac{ \cos(90 - 10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \cos(9 0 - 20) }  = 2 \\  \frac{ \sin(10) }{ \sin(10) }  +  \frac{ \sin(20) }{ \sin(20) }  = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\  \\  \frac{ \cot(40) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(115) }  = 2 \\  \frac{ \cot(90 - 50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \sin(90 + 65) }  = 2 \\  \frac{ \tan(50) }{ \tan(50) }  +  \frac{ \cos(65) }{ \cos(65) }  = 2 \\ 1 + 1 \\  = 2

6 0
3 years ago
What is There are fourteen whole snack bars on a plate. There are five friends.
AleksandrR [38]

Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.

Carl had .5 left of a snack bar.

Dave had .3 left of a snack bar.

Tony had .5 left of a snack bar.

Gary had .0 left of a snack bar.

Tryone had .7 left of a snack bar.

If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.

3 0
3 years ago
CAN SOMEONE PLEASE HELP ME
Hoochie [10]
8) C
9) A
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