PLS I'LL DIRECTLY MARK YOU BRAINLIST (OPTIONS ARE ON THE SECOND SLIDE )

An irrigation system (sprinkler) has a parabolic pattern. The height, in feet, of the spray of water is given by the equation h(

jasenka [17]

9514 1404 393

Answer:

7.5 ft
32.5 ft, 5 ft
10.7 ft

Step-by-step explanation:

a) The starting height is h(0) = 7.5 feet, the constant in the quadratic function.

The irrigation system is positioned 7.5 feet above the ground

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b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...

h(5) = (-5 +10)(5) +7.5 = 32.5 . . . feet

The spray reaches a maximum height of 32.5 feet at a horizontal distance of 5 feet from the sprinkler head.

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c) The maximum distance will be √32.5 + 5 ≈ 10.7 ft.

The spray reaches the ground at about 10.7 feet away.

3 0

2 years ago

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The domain of a quadratic function is all real numbers and the range is y s 2. How many x-intercepts does the

mel-nik [20]

Answer:

There are two x-intercepts.

A quadratic function whose maximum degree two. Therefore, Total two x-intercept possible.

We are given the range of quadratic function y less than equal to 2. It means parabola is downward whose maximum value 2.

Here y is greater than 2 and parabola form downward. Here must be two x-intercept.

If a>0 then form open up parabola.

If a<0 then open down parabola.

Here open down parabola. So, we get total two x-intercept.

Please see the attachment for diagram.

5 0

3 years ago

Find the value of x

svp [43]

X equals x because x is theoretically x the letter

4 0

3 years ago

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One hour after a hiker left a camp, a cyclist set out to catch up. If the hiker traveled 3 miles per hour and the cyclist travel

katrin [286]

Its 23.1 one because in 23 minutes they travel three miles

7 0

2 years ago

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If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$

from (1)(2) => proven

5 0

2 years ago