The change in surface area of Gaussian surface with radius (r) is 8πr.
<h3>Electric field from Coulomb's law</h3>The electric field experienced by a charge is calculated as follows;
where;
The electric field reduces by a factor of
The surface area of a sphere is given as;
Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.
Learn more about area of Gaussian surfaces here: brainly.com/question/17060446
Answer:
Explanation:
Resistance of the tungsten wire
R = resistivity x length / cross sectional area
=
= 107 x 10⁻⁴ ohm
Resistance at 120 degree can be obtained from the following formula
= 155.15 x 10⁻⁴ ohm
= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )
current = 12.5
potential diff = 12.5 x 155.15 x 10⁻⁴ V
= 0 .1939 V
= .19 V
required electric field = potential diff / length of wire
= .1939 / 16 x 10⁻²
= 1.2 N / C
To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.
The vector product between the Force and the radius allows us to obtain the torque, in this way,
Therefore the torque on the particle about the origen is 50k
PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,
Therefore the angle between the ratio and the force is 103.88°
Answer:
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Explanation:
M = Mass of the Earth
m = Mass of satellite
r = Radius of satellite
G = Gravitational constant