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Bingel [31]
3 years ago
6

How can addition patterns help me add mentally?

Mathematics
1 answer:
mylen [45]3 years ago
8 0

Answer:

C) subtract one x block from the left side and subtract two numbered blocks from the right side

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Please help this is including substitution and system of equations.
Darina [25.2K]

Answer: I gotcha

Step-by-step explanation:

B, C, C, D, B

I just helped my brother with this

6 0
3 years ago
Help please!! I’m confused on this question. Thank you!!!
myrzilka [38]

Answer:

Im pretty sure that is an obtuse angle

Step-by-step explanation:

Hope that helps

6 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST! DUE TODAY! WILL GIVE EVERYTHING GOOD!!! HELPP!!! I REALLY NEED HELP ON THIS ONE!!!!
PtichkaEL [24]

Answer:

So its pretty simple

The table provided the Xs so you can just substitute the x in the eqaution becuase the eqaution gives you Y and your looking for Y.

For the first one

-3/4*-16+3=y

12+3=15

So Y is 15

DO the same for the others

Also I think your rate of change is wrong, I think it’s -3/4 but your choice really, I might be wrong

6 0
2 years ago
Read 2 more answers
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
What is the answer to 5x+4=9
Kisachek [45]

Answer:

x=1

Step-by-step explanation:

5x-4=9

5x=9-4

5x=5

x=1

8 0
3 years ago
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