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Vlada [557]
3 years ago
6

Help me solve this worth 30

Mathematics
1 answer:
kirza4 [7]3 years ago
5 0

For the problem on the left, the correct choice is A.

For the problem on the right, the correct choice is B.

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A construction crew is extending the length of the center line on a highway. The length of the line starts out as 6 meters long,
baherus [9]
Gradient of line,m=(17-6)/(20-0)=11/20

finding equation of line using a point (20,17)

y-17=11/20(x-20)
y-17=(11/20x)-11
y=11/20x+(17-11)
y=(11/20)*x+6
4 0
3 years ago
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olya-2409 [2.1K]

Answer:

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Step-by-step explanation:

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In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo
Scorpion4ik [409]

Answer:

x=\frac{8}{3}\ cm

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

A=\frac{1}{2}(AB)(BC)

we have

A=17\ cm^2

AB=(3x-2)\ cm

BC=(x+3)\ cm

substitute the values

17=\frac{1}{2}(3x-2)(x+3)

34=(3x-2)(x+3)

34=3x^2+9x-2x-6

3x^2+7x-6-34=0

3x^2+7x-40=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2+7x-40=0

so

a=3\\b=7\\c=-40

substitute in the formula

x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}

x=\frac{-7(+/-)\sqrt{529}} {6}

x=\frac{-7(+/-)23} {6}

x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}

x=\frac{-7(-)23} {6}=-5

therefore

The solution is

x=\frac{8}{3}\ cm

6 0
3 years ago
Manish and Jhanavi each receive an equal bonus. Manish has 1/2 fraction of allowance as saving accounts , 1/4 of the fraction he
Valentin [98]

Answer:

Manish has Rs630 while Jhanavi has Rs168.

Step-by-step explanation:

The fraction Manish would have left would be subtracting the fraction on savings as well as that spent on the mall. Which would be;

1 -( 1/2 + 1/4)=1 -3/4 = 1/4

Meaning Manish had 1/4 of his allowance left on him.

Which means 1/4 × Rs. 2520=Rs630

Similarly for Jhanavi, we have :

The fraction left as

1-(1/3 +3/5) = 1 - ( 14/15) = 1/15

Meaning 1/15 of the allowance got remains which is;

1/15 × Rs. 2520= Rs.168

3 0
3 years ago
In the early spring, the trout at Big Blue Lake swim at a depth of 30 feet below sea level. When the lake warms up in the summer
Pavel [41]
-50 feet because you have to add 2 to 30 and since it is below sea level, it is a negative
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3 years ago
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