Hello!
Recall that:
![\sqrt[z]{x^{y} }](https://tex.z-dn.net/?f=%5Csqrt%5Bz%5D%7Bx%5E%7By%7D%20%7D)
is equal to 
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
Answer:
Step-by-step explanation:
You can find the area by cutting it across in the middle into a trapezoid and a rectangle.
The trapezoid will have:
height = 10-4 = 6ft
top = 9-6 = 3ft
bottom = 8ft
So its area = 1/2*(3+8)*6 = 33 ft^2
The rectangle will have:
length = 10ft
width = 6ft
So its area = 10*6 = 60 ft^2
Total area = 60+33 = 93 ft^2
Answer:
other
Step-by-step explanation:
you should now this it's too esay in which standard are you. tell in comments
Answer:
The sandbox is most likely in the shape of a kite. As it has only two right angles, it cannot be a square or other form of rectangle. It also cannot be a parallelogram, which has no right angles, nor is it a rhombus- all four sides are not of the same length.
A kite, however, has two pairs of equal-length sides that are adjacent to each other. It also has two sets of equal-measure angles, one of which can be 90° if it is a cyclic kite.
Answer:
Let a = side length of a cube
Let S = surface area of a cube
Area of a square = a²
Since a cube has 6 square sides: S = 6a²
To make a the subject:
S = 6a²
Divide both sides by 6:
Square root both sides:
(positive square root only as distance is positive)
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![\sf x=-3-\sqrt{2} \implies (x+[3+\sqrt{2}])=0](https://tex.z-dn.net/?f=%5Csf%20%20x%3D-3-%5Csqrt%7B2%7D%20%5Cimplies%20%28x%2B%5B3%2B%5Csqrt%7B2%7D%5D%29%3D0)
![\sf x=-3+\sqrt{2} \implies (x+[3-\sqrt{2}])=0](https://tex.z-dn.net/?f=%5Csf%20%20x%3D-3%2B%5Csqrt%7B2%7D%20%5Cimplies%20%28x%2B%5B3-%5Csqrt%7B2%7D%5D%29%3D0)
Therefore,
![\sf y=a(x+[3+\sqrt{2}]) (x+[3-\sqrt{2}])](https://tex.z-dn.net/?f=%5Csf%20y%3Da%28x%2B%5B3%2B%5Csqrt%7B2%7D%5D%29%20%28x%2B%5B3-%5Csqrt%7B2%7D%5D%29)
for some constant a
Given the y-intercept is at (0, -5)
Substituting found value of a into the equation and simplifying:
![\sf y=-\dfrac57(x+[3+\sqrt{2}]) (x+[3-\sqrt{2}])](https://tex.z-dn.net/?f=%5Csf%20y%3D-%5Cdfrac57%28x%2B%5B3%2B%5Csqrt%7B2%7D%5D%29%20%28x%2B%5B3-%5Csqrt%7B2%7D%5D%29)
