Only the third model shows parallel lines cut by a transversal.
We can solve this problem by using some properties that parallel lines cut by a transversal have. First of all, corresponding angles are congruent, and since the angles in figure 1 are corresponding but not congruent, that means that figure one is out.
In addition, in figure two, alternate exterior and interior angles of parallel lines intersected by a transversal are congruent, so since they are not in the picture, that means that this figure is also out.
Figure three is correct because since those are same side interior angles, they need to be supplementary for those to be two parallel lines intersected by a transversal. Since they do, in fact, add up to 180°, that means that the answer is figure three.
Answer: 5225472000
Step-by-step explanation:
Given : The number of bulls = 6
The number of horses = 10
Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .
Also there are two ways to arrange the group pf bulls and horses.
Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_
Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000
Answer:
p(t) = 0.19e0.10t
=>p'(t) = 0.19e0.10t (0.10*1)
=>p'(t) = 0.019e0.10t
t = 0 represents 1994
for 2002, t=2002-1994 =8
in 2002
average price =p(8)
=>average price = 0.19e0.10*8
=>average price =0.422853... million
rate of increase =p'(8)
=>rate of increase = 0.019e0.10*8
=>rate of increase =0.0422853... million per year
p(8)=$ 0.42 million
p'(8)=$ 0.042 million per year
