Steps To Solve:
x² + 6 = 10
~Subtract 6 to both sides
x² + 6 - 6 = 10 - 6
~Simplify
x² = 4
~Take square root of 4
x² = ±√4
~Simplify
x = -2 or x = 2
Best of Luck!
The approximate length of line segment XY is 20.8 units
<h3>
How to calculate the distance between two points</h3>
The formula for calculating the distance between two points is expressed as:
A = √(x2-x1)²+(y2-y1)²
Given the coordinate points X(–12, –6) and Y(5, 6). The distance between them is expressed as;
XY = √(5+12)²+(6+6)²
XY = √(17)²+(12)²
XY = √269 + 144
XY = 20.8
Hence the approximate length of line segment XY is 20.8 units
Learn more on distance formula here; brainly.com/question/661229
Answer:
- 6 bunches of bananas
- 7 pounds of apples
Step-by-step explanation:
We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.
Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...
6B +8(13 -B) = 92
-2B + 104 = 92 . . . . . eliminate parentheses
B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B
13-B = 7 . . . . . . . . . . . the number of pounds of apples
The customer bought 6 bunches of bananas and 7 pounds of apples.
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<em>Comment on the solution</em>
You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.
Answer:
(2,0)
Step-by-step explanation:
Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.
Answer:
5in by 5in by 5in
Step-by-step explanation:
We are not told wat to find but we can as well find the dimension of the prism that will minimize its surface area.
Given
Volume = 125in³
Formula
V = w²h ..... 1
S = 2w²+4wh ..... 2
w is the side length of the square base
h is the height of the prism
125 = w²h
h = 125/w² ..... 3
Substitute eqn 3 into 2 as shown
S = 2w²+4wh
S = 2w²+4w(125/w²)
S = 2w²+500/w
To minimize the surface area, dS/dw = 0
dS/dw =4w-500/w²
0= 4w-500/w²
Multiply through by w²
0 = 4w³-500
-4w³ = -500
w³ = 500/4
w³ =125
w = cuberoot(125)
w = 5in
Get the height
125 =w²h
125 = 25h
h = 125/25
h = 5in
Hence the dimension of the prism is 5in by 5in by 5in
