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4 years ago

The doppler effect is the change in observed frequency due to

Physics

1 answer:

Serga [27]4 years ago

4 0

Answer: relative motion between observer and the sound source.

Explanation: The Doppler effect states that when there is a relative motion between an observer and a sound source the frequency of sound perceived by the observer is different in frequency from the original from the source.

The mathematical back up for this claim is given below.

f' = (v+v') /(v-vs) × f

Where f' = observed frequency

v = speed of sound in air

v' = velocity of observer

vs = velocity of source

f = frequency of sound source.

From the formulae, it can be seen that a change in the value of the velocity of observer (v') and source (vs) produces different value of observed frequency (f').

Note, frequency of sound (f) is a constant.

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A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an

Dominik [7]

Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

mass × g = k × length

put here value and find k

k = $\frac{5*9.8}{.01}$

k = 490 N/m

and ω is

ω = $\sqrt{\frac{k}{m} }$

ω = $\sqrt{\frac{490}{5} }$

ω = 9.9

so here position w.r.t time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

8 0

3 years ago

In a large chemical factory, a feed pipe carries a liquid at a speed of 5.5 m/s. A pump pushes the liquid along at a gauge press

GalinKa [24]

Answer:

v₂ = 15.24 m / s

Explanation:

This is an exercise in fluid mechanics

Let's write Bernoulli's equation, where the subscript 1 is for the factory pipe and the subscript 2 is for the tank.

P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

They indicate the pressure in the factory P₁ = 140000 Pa, the velocity

v₁ = 5.5 m / s and the initial height is zero y₁ = 0

the tank is at a pressure of P2 = 2000 Pa and a height of y₂ = 6.0 m

P₁ -P₂ + ρ g (y₁ -y₂) + ½ ρ v₁² = ½ ρ v₂²

let's calculate

140,000 - 2000 + ρ 9.8 (0- 6) + ½ ρ 5.5² = ½ ρ v₂²

138000 - ρ 58.8 + ρ 15.125 = ½ ρ v2²

v₂² = 2 (138000 /ρ - 58.8 + 15.125)

v₂ = $\sqrt{\frac{276000}{\rho } - 43.675 }$

In the exercise they do not indicate what type of liquid is being used, suppose it is water with

ρ = 1000 kg / m³

v₂ = $\sqrt{\frac{276000}{1000} - 43.675}$

v₂ = 15.24 m / s

5 0

3 years ago

Suppose that a rectangular toroid has 2,000 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i

andrey2020 [161]

Answer:

0.01154 A

Explanation:

We have given the energy in the magnetic field $U=4\times 10^{-6}J$

Value of inductance L =0.060 H

Energy stored in magnetic field is given by $U=\frac{1}{2}Li^2$

$i=\sqrt{\frac{2U}{L}}$

$i=\sqrt{\frac{2\times 4\times 10^{-6}}{0.06}}=0.01154\ A$

So the current flowing through rectangular toroid will be 0.01154 A

3 0

3 years ago

Explain how machines can be useful if the output work is always less than the input work

labwork [276]

People will always have something easy to to there handy work

8 0

3 years ago

A uniform film of a material that has index of refraction 1.30 covers the front surface of a pane made of glass with index of re

Orlov [11]

Answer:

The energy of each photon in the light beam is $1.73\times10^{-18}\ J$ .

Explanation:

Given that,

Index of refraction of glass =1.55

Index of refraction of material =1.30

Wavelength = 115 nm

We need to calculate the energy of each photon in the light beam

Using formula of energy

$E=\dfrac{hc}{\lambda}$

Where, h = Planck constant

$\lambda$ =wavelength

c = speed of light

Put the value into formula

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{115\times10^{-9}}$

$E=1.73\times10^{-18}\ J$

Hence, The energy of each photon in the light beam is $1.73\times10^{-18}\ J$ .

3 0

4 years ago