How do I do solving systems by substitution please help
2 answers:
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Answer:
2
Step-by-step explanation:
We take the equation
and substitute the values for each individual variable in the problem. It looks like this:
Now we can solve the equation.
When solved, it equals 2.
Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (
=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is 32.56 cm.
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Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=36.56.
I hope this helps!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is 32.56 cm.
----------------------------------------------------------
Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=36.56.
I hope this helps!