Answer:
Hydrogen and oxygen bonds
Explanation:
Answer:
2 moles
Explanation:
In one mole of sulfuric acid
There is 2 moles of hydrogen
4 moles of oxygen
and 1 mole of sulfur.
Polyethylene is synthesized from ethylene which is a compound derived from natural gas or petroleum. It’s essentially a thermoplastic, implying that it can be molten and remolded into the desired shape making it reusable and cost-effective. Of all the different kinds of plastics produced around the world, polyethylene is the most common and significant.
Polyethylene is manufactured in three different forms namely:
Low Density Polyethylene (LDPE),High Density Polyethylene (HDPE) andLinear Low Density Polyethylene (LLDPE),
Each of these three plastics has different applications ranging from containers, packaging and films to buckets and bottles.
Hope it helps you...
Answer:
The order of solubility is AgBr < Ag₂CO₃ < AgCl
Explanation:
The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:
Ksp = (A) (B) where A and B are the molar solubilities = s² (for compounds with 1:1 ratio).
It follows then that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:
Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.
Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹² with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of the ratio of ions 2:1 in Ag2CO3, so the answer is not obvious. But since we know that
Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋
Ksp Ag2CO3 = 2s x s = 2 s² = 8.0 x 10-12
s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶
And for AgCl
AgCl ⇄ Ag⁺ + Cl⁻
Ksp = s² = 1.8 x 10⁻¹⁰ ∴ s = √ 1.8 x 10⁻¹⁰ = 1.3 x 10⁻⁵
Therefore, AgCl is more soluble than Ag₂CO₃
The order of solubility is AgBr < Ag₂CO₃ < AgCl