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melomori [17]
4 years ago
9

if you place a crystal substance on a tabletop, return to view it after some time passes, and find it as a powered substance, wh

ich of the following processes most likely took effect?
Chemistry
1 answer:
Goryan [66]4 years ago
5 0
The process which has taken place is called CRYSTALLIZATION.
Generally, crystallization is the process by which solid crystals are precipitated from solution. Crystallization can also occur when a crystal melt or when a crystal get deposited directly from a  gas, although these cases are rarer compare to crystals forming from solutions.
You might be interested in
Calculate the kinetic energy of a truck that has a mass of 2900 kg and is moving at 15 ms
avanturin [10]

Answer:

<h2>326,250 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 2900 \times  {15}^{2}  \\  = 1450 \times 225 \\  = 326250

We have the final answer as

<h3>326,250 J</h3>

Hope this helps you

8 0
3 years ago
Consider the reaction below to answer the following questions (4) a. The nucleophile in the reaction is _______ b. The Lewis aci
KATRIN_1 [288]

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

a) Br^-

b) FeCl3

c) slower

d) see the first attached image

Explanation:

Aromatic compounds undergo electrophilic substitution sections in the presence of the appropriate electrophile.

In the reaction above, the Br^- nucleophile attacks the Lewis acid FeCl3. Recall that the nitro group is meta directing hence the incoming Br^+ electrophile is directed towards the meta position as shown in the image attached.

Note that the nitro group deactivates the ring towards electrophilic substitution hence the reaction is slower with nitrobenzene than with unsubstituted benzene.

5 0
3 years ago
Given the following data, determine the order of reaction with respect to H2.
alex41 [277]

Answer:

First-order with respect to hydrogen.

Explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

r=k*p_{H_2}^m*p_{ICl}^n

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

\frac{r_1}{r_3} =\frac{k*p_{H_2,1}^m*p_{ICl,1}^n}{k*p_{H_2,3}^m*p_{ICl,3}^n}

Thus, we plug in the given rates, and pressures to get:

\frac{1.34}{0.266} =\frac{k*250^m*325^n}{k*50^m*325^n}

So we can cancel wout k and 325^n:

\frac{1.34}{0.266} =\frac{250^m}{50^m}

Next we solve for m, the order of reaction with respect to hydrogen:

5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=\frac{log(5.04)}{log(5)} \\\\m=1.0

It means it is first-order with respect to hydrogen.

Regards!

7 0
3 years ago
Ayuda plis :(<br>Cuando una reacción es de orden cero: ¿porqué se llama orden cero?​
KiRa [710]

Answer:

Revisa la explación detallada, por favor.

Explanation:

¡Hola!

En este caso, teniendo en mente la definición de ley de velocidad, es posible recordar que esta tiene la forma genérica:

r=k[A]^m

En donde k es la constante de velocidad, [A] la concentration de cualquier especie A en la reacción y m el orden the reacción. Ahora, hay tres órdenes de reacción, cero, primer, y segundo orden, y esto pasa cuando m=0, m=1 y m=2 respectivamente. Por lo tanto, si la reacción es de orden cero, la rapidez de reacción resulta igual a la constante de velocidad dado que la concentración estaría elevada a la cero y por consiguiente siempre tendrá valor de 1, por lo que la concentración no afecta la velocidad de reacción. Esto anterior se expresa como:

r=k[A]^0\\\\r=k

¡Saludos!

3 0
3 years ago
Calculate the hydroxide ion concentration in an aqueous solution with a pH of 9.85 at 25°C. 8.7 × 10-10 M 1.4 × 10-10 M 4.2 × 10
Virty [35]

Answer:

7,1x10⁻⁵M = [OH⁻]

Explanation:

pH is the -log of hydronium ion. pOH is -log of hydroxide ion. Knowing pH + pOH = 14:

14 = 9,85 + pOH

pOH = 14 - 9,85

pOH = 4,15

-log [OH⁻] = 4,15

10^-4,15 = [OH⁻]

<em>7,1x10⁻⁵M = [OH⁻]</em>

<em></em>

I hope it helps!

7 0
4 years ago
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