<h3>
Answer:</h3>
12 years
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Explanation:</h3>
We are given;
Half life of hydrogen-3 is 12 years
Initial mass of Hydrogen-3 is 20 grams
Final mass will be 10 g because we are told half of the sample will decay.
To find the time taken for the decay we need to know what half life is;
- Half life is the time taken for a radioactive isotope to decay to half its original amount.
Remaining mass = Original mass × 0.5^n
n = number of half lives
therefore;
10 g = 20 g × 0.5^n
0.5 = 0.5^n
n = log 0.5 ÷ log 0.5
= 1
But, 1 half life is 12 years
Therefore, the time taken is 12 years
Answer:
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Because salt water is denser than freshwater.
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Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g