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ollegr [7]
3 years ago
7

As the temperature of a liquid increases, its viscosity _____. increases stays the same decreases

Chemistry
2 answers:
Olin [163]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

Viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.

For example, honey has high viscosity.

But when we increase the temperature then there occurs more number of collisions between the molecules. Due to this there will be increase in kinetic energy of the molecules and they will be able to move the fluid easily.

As,    Kinetic energy = \frac{3}{2}kT

Thus, we can conclude that as the temperature of a liquid increases, its viscosity decreases.

Valentin [98]3 years ago
5 0
As the temperature of a liquid increases, its viscosity decreases.
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The half-life of hydrogen-3 (tritium) is approximately 12 years. In how many years will half of a 20-gram sample decay by beta r
anyanavicka [17]
<h3>Answer:</h3>

12 years

<h3>Explanation:</h3>

We are given;

Half life of hydrogen-3 is 12 years

Initial mass of Hydrogen-3 is 20 grams

Final mass will be 10 g because we are told half of the sample will decay.

To find the time taken for the decay we need to know what half life is;

  • Half life is the time taken for a radioactive isotope to decay to half its original amount.
  • Using the formula;

Remaining mass = Original mass × 0.5^n

n = number of half lives

therefore;

10 g = 20 g × 0.5^n

0.5 = 0.5^n

n = log 0.5 ÷ log 0.5

  = 1

But, 1 half life is 12 years

Therefore, the time taken is 12 years

4 0
3 years ago
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Answer:  
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3 years ago
Base your answers to questions 74 through 76 on the data table below and on your knowledge of Earth
Serjik [45]

Answer:

See explanation

Explanation:

Now we have, the graph attached.the stable disintegration product of C-14 is N-14.

Then;

Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;

N/No = (1/2)^t/t1/2

N = mass of C-14  at time t

No= mass C-14 originally present

t = time taken for  N amount of C-14 to remain

No = mass of C-14 originally present

t1/2 = half life of C-14

N/64 = (1/2)^17,100/5730

N/64 = (1/2)^3

N/64 = 1/8

8N = 64

N = 8 g

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3 years ago
22) An embryo implants and begins to develop within which structure? *
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A sample of nitrogen gas contains 9.46x10^23 atoms of nitrogen. How much nitrogen is expressed in grams? round your answer to th
Alexxx [7]
  • No of. atoms=9.46×10^23

We know

\boxed{\star{\sf No\;of\:atoms=No\:of\: moles\times Avagadro's\: number}}

\\ \rm\Rrightarrow No\:of\;moles=\dfrac{No\:of\:atoms}{Avagadro's\:no}

\\ \rm\Rrightarrow No\:of\:moles =\dfrac{9.46\times 10^{23}}{6.022\times 10^{23}}

\\ \rm\Rrightarrow No\:of\:moles=1.6mol

Again

\boxed{\star{\sf Mass=Molar\:mass\times No\:of\:moles}}

\\ \rm\Rrightarrow Mass=1.6(14)

\\ \rm\Rrightarrow Mass=22.4g

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