Answer:
x=3 and y=2
Step-by-step explanation:
Let's solve your system by substitution.
4x−3y=6;7x+3y=27
Step: Solve4x−3y=6for x:
4x−3y=6
4x−3y+3y=6+3y(Add 3y to both sides)
4x=3y+6
4x
/4
=
3y+6
/4 (Divide both sides by 4)
x=
3
/4
y+
3
/2
Step: Substitute
3
/4
y+
3
/2 for x in7x+3y=27:
7x+3y=27
7(
3
/4
y+
3
/2
)+3y=27
33
/4
y+
21
/2
=27 (Simplify both sides of the equation)
33
/4
y+
21
/2
+
(−21
/2
)
=27+
(−21
/2)
(Add (-21)/2 to both sides)
33
/4
y=
33
2
<u>33/4y=33/2</u>
33
/4 =33/4 (Divide both sides by 33/4)
y=2
Step: Substitute 2 for y in x=
3
/4
y+
3
/2
x=
3
/4
y+
3
/2
x=
3
/4 (2)+
3
/2
x=3 (Simplify both sides of the equation)
Answer:
x=3 and y=2
HOPE THIS HELPS!!!! :)
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