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podryga [215]
3 years ago
15

Suppose two hosts, A and B, are connected by a 10 Mbps link. The length of a packet is 12 Kb (Kilobits, i.e., 12 × 103 bits). Th

e length of the link is 40 km. Assume that signals propagate at the speed of light (i.e., the ideal speed of 3 × 108 m/s (meters per second)).
Computers and Technology
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

Answer is provided in the explanation section

Explanation:

Given data:

Bandwidth of link = 10* 106 bps

Length of packet = 12* 103 bits

Distance of link = 40 * 103m

Transmission Speed = 3 * 108 meters per second  

Formulas:

Transmission Delay = data size / bandwidth = (L /B) second

Propagation Delay = distance/transmission speed = d/s

Solution:

Transmission Delay = (12* 103 bits) / (10* 106 bps) = 0.0012 s = 1.2 millisecond

Propagation Delay = (40 * 103 meters)/ (3 * 108mps) = 0.000133 = 0.13 millisecond

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class Student(object):

def __init__(self, name, number):

self.name = name

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self.scores.append(0)

 

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def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

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print(student)

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print(student)

 

print("\nSecond student")

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print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

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