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podryga [215]
4 years ago
15

Suppose two hosts, A and B, are connected by a 10 Mbps link. The length of a packet is 12 Kb (Kilobits, i.e., 12 × 103 bits). Th

e length of the link is 40 km. Assume that signals propagate at the speed of light (i.e., the ideal speed of 3 × 108 m/s (meters per second)).
Computers and Technology
1 answer:
Alekssandra [29.7K]4 years ago
4 0

Answer:

Answer is provided in the explanation section

Explanation:

Given data:

Bandwidth of link = 10* 106 bps

Length of packet = 12* 103 bits

Distance of link = 40 * 103m

Transmission Speed = 3 * 108 meters per second  

Formulas:

Transmission Delay = data size / bandwidth = (L /B) second

Propagation Delay = distance/transmission speed = d/s

Solution:

Transmission Delay = (12* 103 bits) / (10* 106 bps) = 0.0012 s = 1.2 millisecond

Propagation Delay = (40 * 103 meters)/ (3 * 108mps) = 0.000133 = 0.13 millisecond

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1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

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GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

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ORDER BY c.City, c.CustomerID

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JOIN Orders o

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ON od.OrderID = o.OrderID

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8 0
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