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podryga [215]
4 years ago
15

Suppose two hosts, A and B, are connected by a 10 Mbps link. The length of a packet is 12 Kb (Kilobits, i.e., 12 × 103 bits). Th

e length of the link is 40 km. Assume that signals propagate at the speed of light (i.e., the ideal speed of 3 × 108 m/s (meters per second)).
Computers and Technology
1 answer:
Alekssandra [29.7K]4 years ago
4 0

Answer:

Answer is provided in the explanation section

Explanation:

Given data:

Bandwidth of link = 10* 106 bps

Length of packet = 12* 103 bits

Distance of link = 40 * 103m

Transmission Speed = 3 * 108 meters per second  

Formulas:

Transmission Delay = data size / bandwidth = (L /B) second

Propagation Delay = distance/transmission speed = d/s

Solution:

Transmission Delay = (12* 103 bits) / (10* 106 bps) = 0.0012 s = 1.2 millisecond

Propagation Delay = (40 * 103 meters)/ (3 * 108mps) = 0.000133 = 0.13 millisecond

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6 0
4 years ago
A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t
Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

   class Program

   { \\ starting the main program

       static void Main(string[ ] args)

       {

           int numberOfDrawers = 0;

           string deskWoodType = "o";

           double cost = 0;

           drawersMeth(numberOfDrawers);

           woodTypeMeth(deskWoodType);

           CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

           OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

       }//end main

       private static void drawersMeth(int numberOfDrawers)

       {

           int numOfDrawers;

           Console.WriteLine("Enter the number of desk drawers");

           numOfDrawers = Convert.ToInt16(Console.ReadLine());

           numberOfDrawers = numOfDrawers;

       }//end drawersMeth

       private static string woodTypeMeth(string deskWoodType)

       {

           Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

           deskWoodType = Convert.ToString(Console.ReadLine());

           switch (deskWoodType)

           {

               case "mahogany":

                   {

                       deskWoodType = "m";

                       break;

                   }

               case "oak":

                   {

                       deskWoodType = "o";

                       break;

                   }

               case "pine":

                   {

                       deskWoodType = "p";

                       break;

                   }

               default:

                   {

                       deskWoodType = "error";

                       break;

                   }

           }

           return deskWoodType;

       }// end woodTypeMeth

       private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

       {

           int pine = 100;

           int oak = 140;

           int other = 180;

           int surchage = 30;

           if (deskWoodType == "p")

               cost = surchage + (numberOfDrawers *pine );

           else if (deskWoodType == "o")

               cost = surchage + (numberOfDrawers *oak );

           else

               cost = surchage + (numberOfDrawers *other );

           return cost;

       }// end CalculateCostMeth

       private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

       {

           double totalCost = cost;

           Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

           Console.WriteLine("The wood finish you have selected is ", deskWoodType);

           Console.WriteLine("The total cost is {0}", totalCost);

       }//end outputCost

   }//end class

}//end nameSpace

5 0
3 years ago
What are the optional parameters when configuring DHCP
stealth61 [152]

Answer:

DHCP is the dynamic host configuration protocol that enable the server for assigning the IP address to the computer. It is basically used to provide automatic IP addresses within the network. It is basically used to configure the default gateway and provide the DNS server data in the device.  

The optional parameter when configuring DHCP are:

  • Sub-net mask
  • Router
  • Domain server
  • Broadcast address
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5 0
3 years ago
"Write code that prints: Ready! countNum ... 2 1 Start! Your code should contain a for loop. Print a newline after each number a
BartSMP [9]

Explanation:

#include <iostream.h>

#inlcude<conion.h>

void main()

{

  int count, x;

  clrscr();

  cout<<"Enter the count:";

  cin>> count;

  cout<<"Ready!\n";

  for(x=count;x>0;x--)

  {

     cout<<x<<"\n";

  }

  cout<<"Start";

  getche();

}

This is a simple program where the output is expected to be in reverse order. So we run a for loop starting from the count and decrements the counter by 1 every time when the loop runs and print the value. So to print the output in "new line" we include "\n".

6 0
3 years ago
Select the correct text in the passage.
oksian1 [2.3K]

Answer:

Answer is given below

Explanation:

The index of the smallest value returned by function positionMin(),

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The input array is given as an argument in function selSort() and it is done by line "public static void selSort(int [] vals)" Here vals is input array argument.

6 0
3 years ago
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