Using features on demand results in saving potentially significant amounts of disk space. features on demand becomes a third ins
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Answer:
Check the explanation
Explanation:
1)
import java.util.*;
public class ArrayStack {
// Declare an Array List
ArrayList<String> aList;
// Constructor that Instantiates arrayList object
ArrayStack() {
aList = new ArrayList<String>();
}
public void push(String object) {
//Add the Value
aList.add(object);
}
public String pop() {
String ret = null;
//Check the size of list if 0 means Stack is Empty
if (aList.isEmpty())
System.out.println("Stack is Empty");
else {
//Return the last value entered as Stack is LAST IN FIRST OUT
// Remove it
ret = aList.get(aList.size() - 1);
aList.remove(aList.size() - 1);
}
return ret;
}
public String peek() {
String ret = null;
//Check the size of list if 0 means Stack is Empty
if (aList.isEmpty())
System.out.println("Stack is Empty");
else {
//Return the last value entered as Stack is LAST IN FIRST OUT
// DO not remove it
ret = aList.get(aList.size() - 1);
}
return ret;
}
public boolean isEmpty() {
//Check the size of list if 0 means Stack is Empty
return aList.size()==0;
}
public static void insertionSort(int arr[], int n)
{
int i, j;
for(i=2;i< n;i++){
arr[0] = arr[i];
j = 1;
while(j <= i-1){
/* implement your code here /*
/* you must start compare arr[j] with a[0], notice that j = 1 */
}
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
ArrayStack aStack = new ArrayStack();
aStack.push("Hey");
aStack.push("Hello");
aStack.push("Bye");
System.out.println(aStack.pop());
System.out.println("Peek: " + aStack.peek());
System.out.println(aStack.pop());
System.out.println(aStack.isEmpty());
System.out.println(aStack.pop());
// int arr[] = new int[] {3,4,2,1,6,7,5};
// insertionSort(arr,7);
// System.out.println(Arrays.toString(arr));
}
}
LinkedQueue
interface QueueInterface {
public void enqueue(Object item);
// Effect: Adds item to the rear of this queue.
// Precondition: This queue is not full.
// Postcondition: item is at the rear of this queue.
public Object dequeue();
// Effect: Removes front element from this queue and returns it.
// Precondition: This queue is not empty.
// Postconditions: Front element has been removed from this queue.
// Return value = (the removed element)
public boolean isEmpty();
// Effect: Determines whether this queue is empty.
// Postcondition: Return value = (this queue is empty)
public boolean isFull();
// Effect: Determines whether this queue is full.
// Postcondition: Return value = (queue is full)
public int size();
}
public class LinkedQueue implements QueueInterface {
private class QueueNode
// Used to hold references to queue nodes for the linked queue
// implementation
{
private Object info;
private QueueNode link;
}
private QueueNode front; // reference to the front of this queue
private QueueNode rear; // reference to the rear of this queue
public LinkedQueue()
// Constructor
{
front = null;
rear = null;
}
public void enqueue(Object item)
// Adds item to the rear of this queue.
{
QueueNode newNode = new QueueNode();
newNode.info = item;
newNode.link = null;
if (rear == null)
front = newNode;
else
rear.link = newNode;
rear = newNode;
}
public Object dequeue()
// Removes front element from this queue and returns it.
{
Object item;
item = front.info;
front = front.link;
if (front == null)
rear = null;
return item;
}
public boolean isEmpty()
// Determines whether this queue is empty.
{
if (front == null)
return true;
else
return false;
}
public Object peek()
// Determines whether this queue is empty.
{
if (front == null)
return null;
else
return front.info;
}
public int size()
// Determines whether this queue is empty
{
QueueNode curr = front;
int count = 0;
while (curr != null) {
++count;
curr = curr.link;
}
return count;
}
public String toString()
// Determines whether this queue is empty.
{
QueueNode curr = front;
String res = "";
while (curr != null) {
res = res + curr.info + " ";
curr = curr.link;
Note that i could not complete the answers to all the question because the codes are above the brainly character limit, you might need to ask the question 2 and 3 separately.
Kindly check the outputs in the attached images below
