The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
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You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
Step-by-step explanation:
Let
We factor 2 to obtain;
We factor the polynomial within the parenthesis by grouping.
We apply difference of two squares on the second factor: 
We now compare to;
It is now obvious that
There are 2 ways to turn a number into a percent...
(1) move the decimal 2 spaces to the right....0.3 = 30%
(2) multiply by 100....0.3 x 100 = 30%
