Since, the fundraiser only have three prices for books($2, $5 and $10), the number of $5 book that was sold is 12.
<h3>How to form equation and solve ?</h3>
The fundraiser only have 3 prices for books which are $2, $5 and $10.
There were 6 more $5 books sold than $10 books sold.
Let
x = number of $10 book sold
Therefore,
number of $5 books sold = x + 6
There are 8 more $2 book sold than $10 book sold. Therefore,
number of $2 books sold = x + 8
A total of $250 was raised.
Therefore, the total amount sold forms the following equation:
10x + 5(x + 6) + 2(x + 8) = 250
10x + 5x + 30 + 2x + 16 = 250
17x = 250 - 30 - 16
17x = 204
x = 204 / 17
x = 12
learn more on equation here: brainly.com/question/27361014
Box B will be cheaper by .48, or 48 cents. Hope I helped! :)
Well first the initial fee would be the x, which is what we have to solve for. Each hour of work is $6, and she does four hours of work. This is equal to $32. The equation would look as follows...
x + 6(4) = 32
Once you have the equation start solving. Use the Pemdas method. First you have to multiply, so now the equation looks as follows...
x + 24 = 32
Now you have to get the x by itself. You do that by subtracting 24 from both sides, because what you do to one side, you do to the other. That will get you to the answer of...
x = 8
In conclusion, Carolina has an initial fee of $8.
Hope this helped.
<h2>
Question:</h2>
1) It's February and you go to the store to buy some food for your pets. You have a Great
Dane and a Savannah cat. The Dane eats 3 times as much as your cat so his food
cost $60 for the big bag and he eats that in one week. The Savannah cats food cost
$15 a bag and it lasts him one week as well. You are there to buy food for the month
and have no more than $300 total to spend. Can you afford a month's worth of food?
a) If you bought the cat 6 weeks worth of food, how many weeks worth can you
buy your Great Dane?
<h2>
Answer: Yes you can afford </h2><h3>
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