Answer:
The magnitude of the net force that produces the deceleration = 1744 N
Explanation:
Using the equations of motion, we can find the deceleration of the car and thereby find the magnitude of the met force that produces such deceleration
v = u + at
where v = final velocity = 18.8 m/s
u = initial velocity = 29.5 m/s
t = 9.14 s
a = ?
v = u + at
18.8 = 29.5 + 9.14a
9.14a = 18.8 - 29.5 = -10.7
a = - 1.171 m/s²
Magnitude of Force causing deceleration = ma = 1490 × 1.171 = 1744 N
Answer:
i have to say whether its correct or wrong yep
Answer:
Part a)
Part b)
Explanation:
Part a)
As we know that flux is defined as
here we have
now we have
Part b)
Also we know that the radius of the planet is given as
now the electric field is given as
here we have
The pressure of the gas is 686 mmhg.
If h = 89 mm
and atmospheric pressure = 775 mmhg
Pressure of the gas = ?
We can find the pressure of the gas by finding the difference between both values.
pressure of the gas = 775 mmhg - 89 mm = 686 mmhg
I assume the 100 N force is a pulling force directed up the incline.
The net forces on the block acting parallel and perpendicular to the incline are
∑ F[para] = 100 N - F[friction] = 0
∑ F[perp] = F[normal] - mg cos(30°) = 0
The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.
Then
F[friction] = 100 N
F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N
If µ is the coefficient of static friction, then
F[friction] = µ F[normal]
⇒ µ = (100 N) / (84.9 N) ≈ 1.2