Answer:
d = (3 i + 5 j) 3 [m] x-distance and 5 [m] y-distance
Explanation:
We can find the displacement if we use a diagram with the cartesian coordinates of the displacement of the mouse.
In the attached image we can see each of the vectors and the origin where the mouse was in the initial position and then the final position after the mouse moved to the right.
So the mouse moved 3 meters to the right and 5 meter upward.
The distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
<h3>Distance from the center of the meter rule</h3>
The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;
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20 A (30 - x)↓ x ↓ 20 cm B 30 cm
2N 0.9N
Let the center of the meter rule = 50 cm
take moment about the center;
2(30 - x) + 0.9(x)(30 - x) = 0.9(20)
(30 - x)(2 + 0.9x) = 18
60 + 27x - 2x - 0.9x² = 18
60 + 25x - 0.9x² = 18
0.9x² - 25x - 42 = 0
x = 29.3 cm
Thus, the distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
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The total capacitance is <em>C</em> such that
1/<em>C</em> = 1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)
Solve for <em>C</em> :
<em>C</em> = 1 / (1/(5.0 µF) + 1/(14 µF) + 1/(21 µF)) ≈ 3.1 µF
All the light in an agn outburst is emitted: a. at the same frequency.
<h3>
What is an agn outburst
?</h3>
An active galactic nucleus (AGN) is a compact area at the core of a galaxy with much higher-than-normal brightness throughout at least some section of the electromagnetic spectrum and features indicating that the luminosity is not created by stars. Excessive non-stellar emission has been reported in radio, microwave, infrared, optical, ultra-violet, X-ray, and gamma ray wavebands. The non-stellar radiation emitted by an AGN is thought to be the product of matter accretion by a supermassive black hole at the heart of its host galaxy.
Active galactic nuclei are the most brilliant and enduring sources of electromagnetic radiation in the cosmos, and as such, they may be utilised to find faraway objects.
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