Answer:
Image will form at distance 22.22 cm behind the mirror
Explanation:
As we know that the mirror formula is given as
![\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cfrac%7B1%7D%7Bd_o%7D%20%3D%20%5Cfrac%7B1%7D%7Bf%7D)
now we know that
object distance from mirror is
![d_o = -50 cm](https://tex.z-dn.net/?f=d_o%20%3D%20-50%20cm)
Focal length of the mirror is given as
![f = 40 cm](https://tex.z-dn.net/?f=f%20%3D%2040%20cm)
now we have
![\frac{1}{-50} + \frac{1}{d_i} = \frac{1}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B-50%7D%20%2B%20%5Cfrac%7B1%7D%7Bd_i%7D%20%3D%20%5Cfrac%7B1%7D%7B40%7D)
![\frac{1}{d_i} = \frac{1}{50} + \frac{1}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%3D%20%5Cfrac%7B1%7D%7B50%7D%20%2B%20%5Cfrac%7B1%7D%7B40%7D)
![d_i = 22.22 cm](https://tex.z-dn.net/?f=d_i%20%3D%2022.22%20cm)
<span>this may help you
As far as the field goes, the two charges opposite each other cancel!
So E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
and since k = 8.99e9N·m²/C²,
E = 1.789e10N·m²/C² * Q / d² </span>
Answer:
hertz (Hz)
The number of periods or cycles per second is called frequency. The SI unit for frequency is the hertz (Hz).
Answer:
I’m pretty sure it’s D
Explanation:
the crust breaks and shifts when that happens
hope dis helps ^-^