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Dimas [21]
3 years ago
10

An object with 5 protons, 5 electrons and 6 neutrons would have what charge

Physics
1 answer:
Anon25 [30]3 years ago
5 0

Answer:

0

Explanation:

The object would be neutral. There are equal numbers of protons and electrons, so the positive and negative charges cancel one another.

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A man has 2 spheres A and B. He gently drops sphere A vertically down and throws the sphere B horizontally at the same time. Whi
anyanavicka [17]

Answer:

The answer is c

Explanation:

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light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to
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<span>Indeed, this is one of the odd results in physics. A system of two polarizing filters arranged as shown below trasmits no light.</span>
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A 12-kg piece of metal displaces 1.6 L of water when submerged. Part A Find its density. Express your answer to two significant
Tatiana [17]

Answer:

ρ = 7500 kg/m³

Explanation:

Given that

mass ,m = 12 kg

Displace volume ,V= 1.6 L

We know that

1000 m ³ = 1 L

Therefore V= 0.0016 m ³

When metal piece is fully submerged

We know that

mass = Density x volume

m=\rho \times V

Now by putting the values in the above equation

\rho=\dfrac{12}{0.0016}\ kg/m^3

ρ = 7500 kg/m³

Therefore the density of the metal piece will be  7500 kg/m³.

6 0
3 years ago
A 60 kg person sits in a chair. How much does the earth pull on the person? (Acceleration due to gravity is -10m/s2) F = mxa → F
MA_775_DIABLO [31]

Answer:

<em>600N(downwards)</em>

Explanations

<em>600N(downwards)</em>

Mas of the person = 60kg

Acceleration due to gravity = -10m/s²

To get the earths pull on the person, we will use the Newton second law of motion;

Force = mass * acceleration;

Force = 60 * -10

Force- -600N

<em>Hence the earth gravitational pull on the person is 600N(downwards). It is downwards due to the negative sign.</em>

<em></em>

7 0
2 years ago
7. A 1000 kg car is rolling down the street at 2.5 m/s. How fast would a 2500 kg car have to
babunello [35]

1 m/s

Explanation:

To solve this question we use the following formula:

momentum = mass × velocity

momentum of the first car = 1000 kg × 2.5 m/s

momentum of the second car = 2500 kg × X m/s

To bring the cars at rest the momentum of the first car have to be equal to the momentul of the second car.

momentum of the first car = momentum of the second car

1000 kg × 25 m/s = 2500 kg × X m/s

X (velocity of the second car) = (1000 × 25) / 2500 = 1 m/s

Learn more about:

momentum

brainly.com/question/13378780

#learnwithBrainly

7 0
3 years ago
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