<span>3 m/s
The slowest possible velocity for the green car will be such that it's velocity matches the velocity of the blue car at the instant the distance between them reaches 0. Reason is simple. If the green car is going faster than the blue car at the moment they reach a distance of 0, then it would be possible for the blue car to go slower. And if the blue car reaches a velocity greater than the green car prior to their touching, then the green car will never reach the blue car.
The blue car's distance as a function of T can be expressed as
b(T) = 0.5 * 0.3 * T^2 = 0.15*T^2
The distance the green car as a function of T can be expressed as
g(T) = (T-5)*V
The velocity of the blue car as a function of T
v(T) = 0.3T
Given the reasoning for the optimal speed, the equation for the green car's location can be rewritten as
g(T) = (T-5)*0.3T
And since we want the distance for both the green and blue cars to match, set the equations equal to each other.
(T-5)*0.3T = 0.15*T^2
Now solve for T
(T-5)*0.3T = 0.15*T^2
0.3T^2 - 1.5T = 0.15T^2
0.15T^2 - 1.5T = 0
We now have a quadratic equation with A = 0.15, B = -1.5, and C=0. Use the quadratic formula to find the roots which are -4.5 and 10. The value of 10 indicates that the interception will occur at T=10, so the velocity has to be
v(T) = 0.3T
v(10) = 0.3*10 = 3 m/s
The minimum speed the green car can have and still reach the blue car is 3 m/s.</span>
Answer:
1. A
sound can't travel through vacuum only
Increase because friction would decrease.
Coating the ramp with a smoother surface will decrease the friction. A decrease in friction will help to slide any object up the ramp easily. Thus, a lesser energy will be spent as compare to earlier. Hence, the ramp's efficiency will increase.
Answer: how to draw a circle
Explanation:
Answer:
Add
Explanation:
When two forces are acting in the same direction then there magnitude are added to each other
Let the first force is and second force is and when they act in same direction then their equivalent will be equal to
When they cat in opposite direction then their equivalent will be