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IRISSAK [1]
3 years ago
5

The diagrams show two planets of different masses with identical orbiting satellites. Select all the conditions that would incre

ase the gravitational force between each pair.
A. move the satellites closer to the planet
B. move the satellites farther from the planet
C. Add mass to the satellites
D.Remove mass from the satellites
Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:

C I think but I'm not sure

Explanation:

Because by adding mass it would add more gravitational pull

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II. IDENTIFY THE TYPE OF FORCE
uysha [10]

Answer:

Explanation:

1. Frictional force is responsible for running of car and buses on roads.

2.Gravitational force exists between astronauts in space.

3. Magnetic for is responsible to attract the iron objects using a magnet

4.Electrostatic force is responsible for fiber to stick on the skin.This force occurs due to the presence of charge.

5.When a person is pushing a trolley then object experience a normal reaction from ground.

6.Gravitational force makes the planet to move in their orbits.

4 0
3 years ago
If a non-rotating object has no acceleration, then we can say for certain that it is:__________
EleoNora [17]

We may be positive that an object is in mechanical equilibrium if it is not rotating and experiences no acceleration.

<h3>What is mechanical equilibrium?</h3>

There are numerous other definitions for mechanical equilibrium that are all mathematically comparable in addition to the definition in terms of force. A system is in equilibrium in terms of momentum if the component motions are all constant. If velocity is constant, the system is in equilibrium in terms of velocity. When an item is in a state of rotational mechanical equilibrium, its angular momentum is preserved and its net torque is zero. More generally, equilibrium is reached in conservative systems at a configuration space location where the gradient of the potential energy concerning the generalized coordinates is zero.

To learn more about mechanical equilibrium, visit:

<u>brainly.com/question/14246949</u>

#SPJ4

6 0
1 year ago
B. Direction: In each of the following situations, identify the method of heat transfer that takes place
Ainat [17]

Answer:

1) Conduction

2)Covection

3)Radiation

4)Convection (Land breeze one of the application of convection of heat)

5) Convection

6)Radiation

7) Radiation

8)Conduction

9) Conduction

10) Radiation

Hope it helps

4 0
3 years ago
1mm is equal to .1 what
bulgar [2K]

Answer:

When you have to do an English-Metric (SI) length conversion, and you already know the English units of length (miles, yards, feet, inches, etc.), all you need to remember is one simple relationship, and you can readily convert any length in the SI system, to the equivalent length in the other.

1 foot (ft) = 0.3048 meters (m)

BIn this case you need your answer in inches. You (hopefully) know there are 12 inches in a foot, so you just do the following:

1 inch (in) = 1/12 ft = 0.3048/12 m = 0.0254 m

8 0
3 years ago
A seagull flies at a velocity of 9.00 m/s straight into the wind.
RideAnS [48]

a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.

b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.

c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

A seagull flies at a velocity,\rm v_{SA}  = 9 \ m/sec

The time the bird takes,t=18.0 min

The distance traveled relative to the earth = 6.00 km

a)

The seagull's relative velocity with reference to the ground as;

\rm v_{sg} = \frac{6.00 \times 10^3 \ m }{(20 min) \times \frac{60 s }{1 \ min}} \\\\ v_{sg}= 5.00 \ m/sec

Air velocity with reference to the ground is;

\rm v_{AG}= v_{SG}-v_{SA} \\\\ v_{AG} = 5.00 \ m/sec - 9.00 \ m/sec \\\\ v_{AG} = -4.00 \ m/sec

b)

If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;

\rm v_{SG}=v_{SA}+v_{AG} \\\\ v_{SG}=-900 \ m/sec +(-4.00 \ m/sec) \\\\ v_{SG}= -13.00 \ m/sec

The time the bird takes;

\rm t = \frac{x_{SG}}{v_{SG}} \\\\ t = \frac{6.00 \times 10^3 \ m }{13.00 \ m/sec } \\\\ t = 462 m/sec \\\\ t = 7  \ min \  and  \ 42  \ sec

c)\

The total round-trip time compared to what it would be with no wind. is;

\rm  t = 20 \ min( \frac{60 \ sec }{1 \ min} )+ 462 \ sec \\\\ t = 1200 \ sec +6 462 \ ec \\\\ t= 1662 \ sec

The time for the round trip is;

\rm  t = \frac{12 \times 10^ 3 }{ 9 \ m/sec }  \\\\ t  = 1333.33 \ sec

Hence the wind's speed, the time bird would need to fly back the total round-trip time will be  4 m/s, 7 minutes and 42 seconds and 1333.33 sec.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

4 0
2 years ago
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