The magnitude of the air drag is 784 N
Explanation:
An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:
where
is the magnitude of the air drag
m is the mass of the object
g is the acceleration of gravity
In this problem, we have
m = 80 kg is the mass of the airman
is the acceleration of gravity
Substituting into the formula, we find:
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For this case we must convert 26 seconds to hours,
By definition we have to:
1 hour equals 3600 seconds.
So, if we propose a rule of three we have:
1 hour ----------> 3600 seconds
x ------------------> 26 seconds
Where the variable "x" represents the number of hours equivalent to 26 seconds:
Thus, 26 seconds equals approximately 0.0072 hours.
Answer:
0.0072 hours
i added an image. i hope it helped :)
