Question

If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s

Answer 1

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

$F_D = mg$

where

$F_D$ is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting into the formula, we find:

$F_D = (80)(9.8)=784 N$

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