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2 years ago

Hisisisisisisiisisiis

Physics

2 answers:

jasenka [17]2 years ago

5 0

Hisisisisisisissisisisisisu

Korolek [52]2 years ago

4 0

............heyyy...

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A racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision

Fudgin [204]

Answer:

The average acceleration of the ball during the collision with the wall is $a=2,800m/s^{2}$

Explanation:

Known Data

We will asume initial speed has a negative direction, $v_{i}=-30m/s$ , final speed has a positive direction, $v_{f}=26m/s$ , $\Delta t=20ms=0.020s$ and mass $m_{b}$ .

Initial momentum

$p_{i}=mv_{i}=(-30m/s)(m_{b})=-30m_{b}\ m/s$

final momentum

$p_{f}=mv_{f}=(26m/s)(m_{b})=26m_{b}\ m/s$

Impulse

$I=\Delta p=p_{f}-p_{i}=26m_{b}\ m/s-(-30m_{b}\ m/s)=56m_{b}\ m/s$

Average Force

$F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}$

Average acceleration

$F=ma$ , so $a=\frac{F}{m_{b}}$ .

Therefore, $a=\frac{2800m_{b} \ m/s^{2}}{m_{b}} =2800m/s^{2}$

8 0

3 years ago

A billiard ball (ball #1) moving at 5.00 m/s strikes a stationary ball (ball #2) of the same mass. after the collision, ball #1

Rashid [163]

If it is completely elastic, you can calculate the velocity of the second ball from the kinetic energy
v1 = velocity of #1 
v1' = velocity of #1 after collision 
v2' = velocity of #2 after collision. 

kinetic energy: v1^2 = v1' ^2 + v2' ^2 (1/2 and m cancel out) 
5^2 = 4.35^2 + v2' ^2 
v2 = 2.46 m/s <--- ANSWER

4 0

2 years ago

Read 2 more answers

Ann (mass 50 kg) is standing at the left end of a 15-m-long, 500 kg cart that has frictionless wheels and rolls on a frictionles

ivanzaharov [21]

Answer:

13.5 m

Explanation:

M = Mass of cart = 500 kg

m = Ann's mass = 50 kg

$v_m$ = Velocity of Ann relative to cart = 5 m/s

$v_M$ = Velocity of Cart relative to Ann

As the linear momentum of the system is conserved

$Mv_M+mv_m=0\\\Rightarrow v_M=-\frac{mv_m}{M}\\\Rightarrow v_M=-\frac{50\times 5}{500}\\\Rightarrow v_M=-0.5\ m/s$

Time taken to reach the right end by Ann

$Time=\frac{Distance}{Speed}\\\Rightarrow Time=\frac{15}{5}=3\ s$

Distance the cart will move in the 3 seconds

$Distance=Speed\times Time\\\Rightarrow Distance=-0.5\times 3=-1.5\ m$

The negative sign indicates opposite direction

Movement of Ann will be the sum of the distances

$15+(-1.5)=13.5\ m$

The net movement of Ann is 13.5 m

5 0

2 years ago

Which would likely demagnetize a magnetized iron nail?

olga2289 [7]

The answer to this question is dropping it on a hard surface.

8 0

3 years ago

The 6 strings on a guitar all have about the same length and are stretched with about the same tension.The highest string vibrat

ahrayia [7]

Answer:

B. d(low)=4d(high)

Explanation:

Frequency of a string can be written as;

f = v/2L

Where;

v = sound velocity

L = string length

Frequency can be further expanded to;

f = v/2L = (1/2L)√(T/u) ......1

Where;

m= mass,

u = linear density of string,

T = tension

p = density of string material

A = cross sectional area of string

d = string diameter

u = m/L .......2

m = pAL = p(πd^2)L/4 (since Area = (πd^2)/4)

f = (1/2L)√(T/u) = (1/2L)√(T/(m/L))

f = (1/2L)√(T/((p(πd^2)L/4)/L))

f = (1/2L)√(4T/pπd^2)

f = (1/L)(1/d)√(4T/pπ)

Since the length of the strings are the same, the frequency is inversely proportional to the string diameter.

f ~ 1/d

So, if

4f(low) = f(high)

Then,

d(low) = 4d(high)

6 0

3 years ago