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Rom4ik [11]
3 years ago
13

Hisisisisisisiisisiis

Physics
2 answers:
jasenka [17]3 years ago
5 0
Hisisisisisisissisisisisisu
Korolek [52]3 years ago
4 0
............heyyy...
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If the mass of an object is 200kg and the applied force is 2600N, calculate the Acceleration.​
Aliun [14]

Answer:

<em>13 m/s²</em>

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration  = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m  (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

6 0
3 years ago
Which of the following does notaccurately describe the forces that exist with an atom? 
natima [27]
The believe the answer to this is B
8 0
3 years ago
A 5 .0kg cart is moving horizontaly at 6 .0m/s in order to change its speed to 10m/s the net work done on the cart must be
ahrayia [7]

Answer:

the net work done on the cart is 160 J.

Explanation:

Given;

mass of the cart, m = 5.0 kg

initial velocity of the cart, u = 6 m/s

final velocity of the cart, v = 10 m/s

The net work done on the cart is equal to change in average kinetic energy of the cart;

W = K.E = \frac{1}{2} m(v^2-u^2)\\\\W = \frac{1}{2} \times 5(10^2-6^2)\\\\W = 160 \ J

Therefore, the net work done on the cart is 160 J.

8 0
3 years ago
The largest of the terrestrial planets is _____.
vladimir1956 [14]
The terrestrial planets are those that are similar to Earth. In Laint terra means Earth and Earth is Tierra.

The terrestrial planets have solid surface made up of rocks and metals.

There are four terrestrial planet in our planetary (solar) system: Mercury, Venus, Earth and Mars.

You can verify the sizes of those planets in many places.

Earth is the largest of the terrestrial planets.

3 0
3 years ago
Read 2 more answers
A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displ
sladkih [1.3K]

Answer:

Explanation:

Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k

Initial potential energy is

PE = ½kA²

As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

½kx² = ½(½kA²)

    x² = ½A²

    x = (√0.5)A

    x ≈ 0.707A

just plug in your actual starting position A

With A = 5.2 cm

x = 3.67695... 3.7 cm

5 0
3 years ago
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