Question

10=16(x-2)^2+10 show work

Answer 1

$Cancel \ 10 \ on \ both \ sides.\\\\0 = 16(x - 2)^2\\\\\\Divide \ both \ sides \ by \ 16.\\0 = (x - 2)\\\\\\Now take the square root of both sides.\\\\0 = x - 2\\\\\\Add 2 to both sides.\\\\2 = x\\\\Switch sides.\\\\\fbox{x = 2}$

Answer 2

Answer:

x=2

Step-by-step explanation:

10=16(x-2)^2+10

Subtract 10 from each side

10-10=16(x-2)^2+10-10

0 =16(x-2)^2

Divide by 16

0/16 = 16/16 (x-2)^2

0 = (x-2)^2

Take the square root of each side

sqrt(0) = sqrt(  (x-2)^2)

0 = x-2

Add 2 to each side

0+2 = x-2+2

2 =x