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vladimir1956 [14]
3 years ago
13

How did the cathode ray tube contribute to the history of atomic structure?

Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0
J.J Thompson discovered the electron. He demonstrated that cathode rays were negatively charged. He then realized that the accepted model of an atom did not come out positive nor negative
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They stay the same

Explanation:

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3 years ago
Draw a physical model that shows the reaction of zinc metal and hydrochloric acid (hydrogen chloride).
Brilliant_brown [7]

Answer:

Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas

Zn + 2HCI - ZnCl2 + H2

Explanation:

Be sure to label your model to clearly show how you are representing the atoms

3 0
2 years ago
When do replicated chromosomes are aligned in the center
Art [367]

Answer:

<u>During Metaphase</u>

<u></u>

Explanation:

During Metaphase the cell chromosome align themselves in the middle of the cell.This occur due to a cellular process called "Tug of War".

The chromosome which have been replicated and joined at the central point  called centromere are called sister chromatids

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Therse is important checkpoint in the middle of mitosis called<u> metaphase.</u>

At this point cell ensure that , it is ready to divide or not.

Once the cell ensure that everything is ready to divide. Only after then , yhe cell enters the fourth phase called <u>anaphase.</u>

7 0
2 years ago
The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml
inn [45]
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>

8 0
2 years ago
Use the information below to explain why the atomic radius decreases down a group.
notsponge [240]

Answer:

Detail is given below

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

In A we can see that there is one positive charge and force of attraction is 2.30×10⁻⁸ N and distance is 0.10 nm

In B we can see that negative charge is further away from nucleus because of greater distance thus force of attraction will be less. 0.58×10⁻⁸ N

In C this distance further increases and force also goes in decreasing 0.26×10⁻⁸ N.

3 0
3 years ago
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