Answer:
h = 10000 m
Explanation:
The pressure applied at a depth of the liquid is given by:
P =ρgh
where,
P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)
P = (1000)(101325 Pa) = 1.01 x 10⁸ Pa
ρ = Density of sea water = 1025 kg/m³
g = 9.8 m/s²
h = maximum depth to survive = ?
Therefore,
1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h
h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)
<u>h = 10000 m</u>
The phenomena<span> of </span>atmospheric<span> electricity are of three kinds. ..... In the Earth-</span>ionosphere cavity, the electric field<span> and conduction current in the lower </span>atmosphere<span> </span>
<span>a) 1960 m
b) 960 m
Assumptions.
1. Ignore air resistance.
2. Gravity is 9.80 m/s^2
For the situation where the balloon was stationary, the equation for the distance the bottle fell is
d = 1/2 AT^2
d = 1/2 9.80 m/s^2 (20s)^2
d = 4.9 m/s^2 * 400 s^2
d = 4.9 * 400 m
d = 1960 m
For situation b, the equation is quite similar except we need to account for the initial velocity of the bottle. We can either assume that the acceleration for gravity is negative, or that the initial velocity is negative. We just need to make certain that the two effects (falling due to acceleration from gravity) and (climbing due to initial acceleration) counteract each other. So the formula becomes
d = 1/2 9.80 m/s^2 (20s)^2 - 50 m/s * T
d = 1/2 9.80 m/s^2 (20s)^2 - 50m/s *20s
d = 4.9 m/s^2 * 400 s^2 - 1000 m
d = 4.9 * 400 m - 1000 m
d = 1960 m - 1000 m
d = 960 m</span>
Answer:
Explanation:
12.0 kv primary voltage
315 kv secondary voltage ( converted voltage ) V1 or Vo
v2 (Vn)= 730 kv new secondary voltage
a) Ratio of turns in 730 kv to turns in 315 kv
= therefore the ratio of turns = 2.317 ≈ 2.32
B) ratio of the new current output to the old current output for the same power input to the transformer
since the power input is the same
equation 1
Vp = primary voltage, Vo = old secondary voltage, Vn = new secondary voltage, In = new secondary current, Io = old secondary current
therefore equation 1 becomes
= 315 / 730 = 0.43