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Ronch [10]
3 years ago
14

A train travels due south at 25 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of e

ach raindrop makes an angle of 66° with the vertical, as measured by an observer stationary on the ground. An observer on the train, however, sees the drops fall perfectly vertically. Determine the speed of the raindrops relative to the ground.

Physics
1 answer:
olasank [31]3 years ago
8 0

Answer:

Explanation:

Given

Train travels towards south with a velocity if v_t=25\ m/s

Rain makes an angle of \theta =66^{o}  with vertical

If an observer sees the drop fall perfectly vertical i.e. horizontal component of rain velocity is equal to train velocity

suppose v_r is the velocity of rain with respect to ground then

v_r\sin\theta =v_t

v_r\times \sin (66)=25

v_r=27.36\ m/s

Therefore velocity of rain drops is 27.36 m/s              

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An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu
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(a) 1200 rad/s

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\alpha = \frac{\omega_f - \omega_i}{t}

where we have

\alpha = -80.0 rad/s^2 is the angular acceleration (negative since the rotor is slowing down)

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(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

\omega_f=0 is the final angular speed

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Solving the equation,

t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s

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The velocity of the canoe is  1.7 m/s.

<h3>What is momentum?</h3>

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