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Ronch [10]
3 years ago
14

A train travels due south at 25 m/s (relative to the ground) in a rain that is blown toward the south by the wind. The path of e

ach raindrop makes an angle of 66° with the vertical, as measured by an observer stationary on the ground. An observer on the train, however, sees the drops fall perfectly vertically. Determine the speed of the raindrops relative to the ground.

Physics
1 answer:
olasank [31]3 years ago
8 0

Answer:

Explanation:

Given

Train travels towards south with a velocity if v_t=25\ m/s

Rain makes an angle of \theta =66^{o}  with vertical

If an observer sees the drop fall perfectly vertical i.e. horizontal component of rain velocity is equal to train velocity

suppose v_r is the velocity of rain with respect to ground then

v_r\sin\theta =v_t

v_r\times \sin (66)=25

v_r=27.36\ m/s

Therefore velocity of rain drops is 27.36 m/s              

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1.Which statement is true when two objects are 20 miles apart but one is much bigger?
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1. C.  Gravitational attraction exists between the two objects.

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A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens p
Kipish [7]

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

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