Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
Answer:
The fluids speed at a) 
and b) 
are 
and 
respectively
c) Th volume of water the pipe discharges is: 
Explanation:
To solve a) and b) we should use flow continuity for ideal fluids:
(1)
With Q the flux of water, but Q is 
using this on (1) we have:
(2)
With A the cross sectional areas and v the velocities of the fluid.
a) Here, we use that point 2 has a cross-sectional area equal to 
, so now we can solve (2) for 
:
b) Here we use point 2 as 
:
c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is 
, so we can write:
, solving for V:
Answer:
Heating water to produce steam which drives a turbine
Explanation:
Generation of electricity in coal-burning power plants and nuclear power plants both involve heating water to produce steam which drives a turbine.
Answer:
what is the answers? i cant help you without the answers
Explanation:
Answer:
1.68m/s^2
Explanation:
using V^2=U^2+2×a×s formula.
If,
(Final Velocity)V=45
(Initial Velocity)U=0 because it starts from rest
(Distance)S=600m
(acceleration)a= ?
now,
using formula,
45^2=0^2+2×a×600
2025= 1200a
a=2025÷1200
a = 1.68m/s^2(The unit of acceleration is m/s^2)
Therefore the acceleration is 1.68m/s^2
Hope it works !!!
