All categories

4 years ago

How will the equation of morion for an object moving with an ununifor motion change????? please help me !!!!!!

Physics

1 answer:

babymother [125]4 years ago

4 0

Answer:

The equation of motion is derived based on the Newton’s laws of motion. And it changes accordingly when an object changes with uniform velocity.

Given is that object moves with uniform velocity, that is no change in velocity so there will no acceleration.

As we know

Here, u = v (due to uniform velocity)

1st equation of motion is, v = u + at

2nd equation of motion,

3rd equation of motion,

Explanation:

You might be interested in

Charges q, q, and – q are placed on the x-axis at x = 0, x = 4 m, and x = 6 m, respectively. At which of the following points do

MrRissso [65]

Answer:

can you show a graph but if not i believe the answer is x=6m

Explanation:

7 0

3 years ago

Which statement correctly describes gravity?

Advocard [28]

Answer:

a force that attracts matter to the earth

Explanation:

depends on where you are the gravity can be different in space there is no gravity on Earth there is , that's why when you jump you come back down

5 0

3 years ago

The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2,716.5 feet) and has more than 160 stories.

Elena L [17]

Answer:

h = 599.5 m

Explanation:

Given,

height of structure = 828 m

weight of the tourist = 184 lb

= 184 x 0.45359 = 83.43 Kg

Potential energy = 187000 J

PE = m gd

$d = \frac{PE}{mg}$

$d = \frac{187000}{83.43\times 9.81}$

h = 228.5 m

Height of the room above the ground.

h = 828 - 228.5

h = 599.5 m

Height of the floor above ground is equal to 599.5 m.

4 0

3 years ago

Help! <br><br> I need to do this quickly!!!

umka2103 [35]

D is the answer. It is a firm statement.

8 0

2 years ago

Initially a car accelerates at 2 m/s2 for x seconds. The car then travels at a velocity of -6 m/s for x seconds. If the car disp

Luda [366]

Answer:

The time travel is

t=8 s

Explanation:

$a= 2 \frac{m}{s^{2} } \\v=-6 \frac{m}{s} \\x=16m$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*t+\frac{1}{2} *2*t^{2}$

$t^{2}-6*t-16=0\\ using :\\\frac{-b+/-\sqrt{b^{2}-4*c*a } }{2} \\\frac{-(-6)+/-\sqrt{(-6)^{2}-4*(-16)*(1) } }{2}=\frac{3}{2} +/- \frac{10}{2} \\t_{1} = 2s \\t_{2} = 8s$

Check

$t_{2}=8s$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*+\frac{1}{2} *2*8^{2}$

$x_{f}=-48+64\\x_{f}=16$

5 0

4 years ago