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3 years ago

How will the equation of morion for an object moving with an ununifor motion change????? please help me !!!!!!

Physics

1 answer:

babymother [125]3 years ago

4 0

Answer:

The equation of motion is derived based on the Newton’s laws of motion. And it changes accordingly when an object changes with uniform velocity.

Given is that object moves with uniform velocity, that is no change in velocity so there will no acceleration.

As we know

Here, u = v (due to uniform velocity)

1st equation of motion is, v = u + at

2nd equation of motion,

3rd equation of motion,

Explanation:

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You attach a 2.90 kg mass to a horizontal spring that is fixed at one end. You pull the mass until the spring is stretched by 0.

Murljashka [212]

Answer:

Explanation:

The spring is stretched by .5 m and then released that means its amplitude of oscillation A is 0.5 m .

A = 0.5 m

After the release at one extreme point , the mass comes to rest again at another extreme point after half the time period ie

T / 2 = .3 s

T = 0.6 s

Angular velocity

ω = $\frac{2\times \pi}{T}$

ω = $\frac{2\times \pi}{0.6}$

ω = 10.45

Maximum velocity = ω A

ω and A are angular velocity and amplitude of oscillation.

Maximum velocity = 10.45 x .5

= 5.23 m /s

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3 years ago

Which category of energy originates in the process of photosynthesis?

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2 years ago

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A ball thrown vertically upward reaches a certain height and comes down again. What can you say about its kinetic energy at the

MrRissso [65]

The K.E. at the maximum height is zero, no matter what that height is.

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3 years ago

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Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the

Alenkasestr [34]

Answer:

The acceleration of car 2 is four times of the acceleration of car 1.

Explanation:

The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :

$a=\dfrac{v^2}{r}$

In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.

So,

$\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}$

1 and 2 represent car 1 and car 2 respectively.

$v_2=2v_1$

So,

$\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1$

So, the acceleration of car 2 is four times of the acceleration of car 1.

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3 years ago

Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det

Leokris [45]

Answer:

0.037 N/m

Explanation:

The web acts as a spring, so it obeys Hook's law:

$F=kx$ (1)

where

F is the force exerted on the web

k is the spring constant

x is the stretching/compression of the web

In this problem, we have:

- The mass of the fly is $m=15 mg=15\cdot 10^{-6} kg$

- The force exerted on the web is the weight of the fly, so:

$F=mg=(15\cdot 10^{-6}kg)(9.81 m/s^2)=1.47\cdot 10^{-4}N$

- The stretching of the web is

$x=4.0 mm=0.004 m$

So if we solve eq.(1) for k, we find the spring constant:

$k=\frac{F}{x}=\frac{1.47\cdot 10^{-4} N}{0.004 m}=0.037 N/m$

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3 years ago