The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t - (6.2 m/s3)t2. What is the ave
1 answer:
Answer:
average acceleration = −14.5 m/s²
so correct option is B) -14 m/s²
Explanation:
given data
v(t) = (2.3 m/s) + (4.1 m/s2)t - (6.2 m/s3)t²
t1 = 1.0 s
t2 = 2.0 s
to find out
What is the average acceleration
solution
we know that average rate of change on the interval is
average acceleration = ............1
so here put value of t for final f and initial i
we get Vf = 2.3 + (4.1)(2) - (6.2)(2)²
and Vi = 2.3 + (4.1)(1) - (6.2)(1)²
and t2 - t1 = 2 - 1 = 1 s
put value in equation 1
average acceleration = [2.3 + (4.1)(2) - (6.2)(2)² ] - [ 2.3 + (4.1)(1) - (6.2)(1)² ]
average acceleration = −14.5 m/s²
so correct option is B) -14 m/s²
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