Question

Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small segment with angle θ is labeled δq. Determine the magnitude of the electric field. The total charge is 53.2μC ,the radius of the semicircle is 84 cm, and the Coulomb constant is 8.987×10^9 Nm^2/C^2.

Answer 1

Answer: Magnitude of electric field = 6.77×10^11N/C

Explanation: Electric field= E =KQ/ r ^2

Given:

Total charge Q=53.2nc

Radius 84cm= 0.84m

Coulombs constant K= 8.987x10^9NmC^-1

E =(( 8.987×10^9) × 53.2) /(0.84^2)

E = ( 4 . 777 ×10 ^ 9 )/ 0.7056

E = 6.77 × 10^ 11 NC^-1