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Bas_tet [7]
3 years ago
13

Who would you be friends with

Physics
2 answers:
Firdavs [7]3 years ago
6 0

Answer:

A nice person

Explanation:

Vadim26 [7]3 years ago
5 0

Answer:

a good friend

Explanation:

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Identify two factors that increase the electric force between objects
jok3333 [9.3K]

Answer: The distance between particles, and the amount of electric charge they carry.

Explanation:

Charles Coulomb wanted to figure out the strength of the force between two objects and these were the two most independent factors.

8 0
2 years ago
The air pressure inside a car tire is
Valentin [98]

Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

Force = 41,500N

Pressure = 3.00atm

since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

Get the area

Area = Force/Pressure

Area = 41500/303,975

Area = 0.137m²'

Hence the surface area of the  inside of the tire is 0.137m²

7 0
3 years ago
What is a dwarf planet???
Oliga [24]
Its a very small planet
6 0
3 years ago
Read 2 more answers
A heavy rope, 80 ft long and weighing 32 lbs, hangs over the edge of a building 100 ft high. how much work w is done in pulling
allochka39001 [22]
The first thing you should know for this case is that work is defined as the product of force by the distance traveled in the direction of force.
 We have then:
 W = Fd
 The distance varies, so we must integrate:
 from 0 to 20:
 W = ∫F (x) dx
 W = ∫32xdx
 W = 32∫xdx
 W = 32 (x ^ 2/2) = (16) (20 ^ 2) = 6400 ft * lbs
 answer:
 6400 ft * lbs is work done pulling the rope up 20 ft
6 0
3 years ago
Find the three longest wavelengths (call them λ1, λ2, and λ3) that "fit" on the string, that is, those that satisfy the boundary
zepelin [54]
If you have a string that is fixed on both ends the amplitude of the oscillation must be zero at the beginning and the end of the string. Take a look at the pictures I have attached. It is clear that  our fundamental harmonic will have the wavelength of:
\lambda_1=\frac{L}{2}
All the higher harmonics are just multiples of the fundamental:
\lambda_n=n\lambda_1\\ \lambda_n=n\frac{L}{2}
Three longest wavelengths are:
n=3; \lambda_3=\frac{3L}{2}\\
n=2; \lambda_2=L\\
n=1; \lambda_=\frac{L}{2}\\


6 0
3 years ago
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