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3 years ago

What weight of water is displaced by a 100-ton floating ship? What is the buoyant force that acts on this ship?

1 answer:

3 0

An object that weighs 100 tons and is floating is displacing exactly 100 tons of the fluid, and the buoyant force on it is 100 tons. The vertical forces on it are balanced (add up to zero), and that's why it isn't accelerating up or down.

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When scientists observed the light from stars and galaxies, they noticed that their color shifted toward the end of the visible

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Color shifted towards the end is C red

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3 years ago

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How many structures do prokaryotic cells have in common with the eukaryotic cells?

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Two. The both have a plasma membrane and cytoplasm.

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3 years ago

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Squids propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracting the cavity

Musya8 [376]

Answer:

v_squid = - 2,286 m / s

Explanation:

This exercise can be solved using conservation of the moment, the system is made up of the squid plus the water inside, therefore the force to expel the water is an internal force and the moment is conserved.

Initial moment. Before expelling the water

p₀ = 0

the squid is at rest

Final moment. After expelling the water

$p_{f}$ = M V_squid + m v_water

p₀ = p_{f}

0 = M V_squid + m v_water

c_squid = -m v_water / M

The mass of the squid without water is

M = 9 -2 = 7 kg

let's calculate

v_squid = 2 8/7

v_squid = - 2,286 m / s

The negative sign indicates that the squid is moving in the opposite direction of the water

8 0

4 years ago

Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the

saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

$R=\alpha \frac{l}{s}$

Were:

R is resistance

$\alpha$ is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area ( $s=\pi r^{2}$ ).

So if the lenght and radius are doubled, the equation goes as follows:

$R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }$

So finally because the circular area is a square function, the resulting equation is half of the one before.

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3 years ago

Two identical conducting spheres each having a radius of 0.500 cm are connected by a light, 1.90-m-long conducting wire. A charg

Ivan

Answer: 4.19 N

Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.

As the wire is a conductor the spheres are at same potential so we have:

V1=V2

V1=k*Q1/r1 and V2=k*Q2/r2

where r1=r2, then

Q1=Q2

so the electric force is given by:

F=k*Q^2/d^2 where d is the distance between the spheres.

Finally replacing the values, we have

F=9*10^9(41*10^-6)^2/(1.9)^2= 4.19 N

8 0

3 years ago