Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
b(NaCl) = n(NaCl) ÷ m(H₂O).
b(NaCl) = 0,244 mol ÷ 0,0957 kg.
b(NaCl) = 2,55 mol/kg.
Answer:
69
Explanation:
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A is the answer im pretty sure
The two oxygen atoms share two pairs of electrons, so two covalent bonds hold the oxygen molecule together
Answer:
53% aluminium is present.
Explanation:
Given data:
Mass of aluminium in bauxite = 108 g
Total mass of sample = 204 g
Percentage of aluminium = ?
Solution:
Formula:
Percentage = Mass of aluminium / total mass of sample× 100
Now we will put the values in formula:
Percentage = 108 g/204 × 100
Percentage = 0.53 × 100
Percentage = 53%
So in given 204 g of bauxite there is 53% aluminium is present.
